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"""
https://leetcode.com/problems/combination-sum/
"""
"""
Given a set of candidate numbers (candidates) (without duplicates) and a target number (target),
find all unique combinations in candidates where the candidate numbers sums to target.
The same repeated number may be chosen from candidates unlimited number of times.
Note:
All numbers (including target) will be positive integers.
The solution set must not contain duplicate combinations.
Example 1:
Input: candidates = [2,3,6,7], target = 7,
A solution set is:
[
[7],
[2,2,3]
]
Example 2:
Input: candidates = [2,3,5], target = 8,
A solution set is:
[
[2,2,2,2],
[2,3,3],
[3,5]
]
"""
class Solution:
def combinationSum(self, candidates, target):
results = []
candidates.sort()
self.search(candidates, target, results, [])
return results
def search(self, candidates, target, results, result):
for i in range(len(candidates)):
temp = target
if candidates[i]<=temp:
temp -= candidates[i]
if temp == 0:
l = result+[candidates[i]]
l.sort()
if l not in results:
results.append(l)
break
else:
self.search(candidates, temp, results, result+[candidates[i]])
else:
break
x = Solution()
print(x.combinationSum([8,7,4,3], 11))