-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy path7_Reverse_Integer.py
More file actions
60 lines (53 loc) · 1.23 KB
/
Copy path7_Reverse_Integer.py
File metadata and controls
60 lines (53 loc) · 1.23 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
"""
https://leetcode.com/problems/reverse-integer/
Given a 32-bit signed integer, reverse digits of an integer.
Example 1:
Input: 123
Output: 321
Example 2:
Input: -123
Output: -321
Example 3:
Input: 120
Output: 21
Note:
Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−2^31, 2^31 − 1].
For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.
"""
"""
正常思维,int->str->int,反转字符串,很慢
"""
"""
class Solution:
def reverse(self, x: 'int') -> 'int':
up = -2**31
if(x < up or x > -up-1):
return 0
s = str(x)
result = ""
if(x<0):
result+='-'
s = s[1:]
result += s[::-1]
a = int(result)
if(a < up or a > -up-1):
return 0
return a
x = Solution()
print(x.reverse(0))
"""
"""
int->int faster than before
"""
def reverse(x: 'int') -> 'int':
result = 0
if x<0:
symbol = -1
x = -x
else:
symbol = 1
while x:
result = result*10+x%10
x//=10
return 0 if result > pow(2, 31) else result * symbol
print(reverse(123))