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Treap on implicit keys.cpp
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149 lines (134 loc) · 2.87 KB
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#include <bits/stdc++.h>
using namespace std;
ifstream fin("grid.in");
ofstream fout("grid.out");
struct treapNode {
treapNode* l;
treapNode* r;
int key, prior, sz;
};
using ptr = treapNode*;
using pt = pair<ptr, ptr>;
const int mod = 1610612741;
ptr emptyNode = new treapNode{nullptr, nullptr, 0, -1, 0};
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
int n, k;
void updateNode(ptr node) {
if (node != emptyNode) {
node->sz = node->l->sz + 1 + node->r->sz;
}
}
void heapify(ptr node) {
if (node == emptyNode) {
return;
}
ptr best = node;
if (best->prior < node->l->prior) {
best = node->l;
}
if (best->prior < node->r->prior) {
best = node->r;
}
if (best != node) {
swap(node->prior, best->prior);
heapify(best);
}
}
treapNode* build(int st, int dr, int lin) {
int mid = (st + dr) / 2;
treapNode* node = new treapNode{emptyNode, emptyNode, mid + lin * n, rng() % mod, 1};
if (st < mid) {
node->l = build(st, mid - 1, lin);
}
if (mid < dr) {
node->r = build(mid + 1, dr, lin);
}
heapify(node);
updateNode(node);
return node;
}
pt split(ptr node, int k) {
if (node == emptyNode) {
return {emptyNode, emptyNode};
}
if (node->l->sz < k) {
pt p = split(node->r, k - node->l->sz - 1);
node->r = p.first;
updateNode(node);
return {node, p.second};
}
pt p = split(node->l, k);
node->l = p.second;
updateNode(node);
return {p.first, node};
}
ptr join(ptr A, ptr B) {
if (A == emptyNode) {
return B;
}
if (B == emptyNode) {
return A;
}
if (B->prior < A->prior) {
A->r = join(A->r, B);
updateNode(A);
return A;
}
B->l = join(A, B->l);
updateNode(B);
return B;
}
int getElement(ptr node, int k) {
if (node->l->sz + 1 == k) {
return node->key;
}
if (k <= node->l->sz) {
return getElement(node->l, k);
}
return getElement(node->r, k - node->l->sz - 1);
}
ptr ins(ptr node, int k, ptr newNode) {
pt p = split(node, k - 1);
return join(join(p.first, newNode), p.second);
}
ptr del(ptr node, int k) {
pt p1 = split(node, k - 1);
pt p2 = split(p1.second, 1);
return join(p1.first, p2.second);
}
void dfs(ptr node) {
if (node == emptyNode) {
return;
}
dfs(node->l);
fout << node->key << ' ';
dfs(node->r);
}
void testCase() {
fin >> n >> k;
ptr roots[3];
for (int i = 0; i < 3; ++i) {
roots[i] = build(1, n, i);
}
for (int i = 0; i < k; ++i) {
int x1, y1, x2, y2;
fin >> x1 >> y1 >> x2 >> y2;
y1 += 1, y2 += 1;
int key = getElement(roots[x1], y1);
roots[x1] = del(roots[x1], y1);
roots[x2] = ins(roots[x2], y2, new treapNode{emptyNode, emptyNode, key, rng() % mod, 1});
}
for (int i = 0; i < 3; ++i) {
dfs(roots[i]);
fout << '\n';
}
}
int main() {
int tests = 1;
for (int tc = 0; tc < tests; ++tc) {
testCase();
}
fin.close();
fout.close();
return 0;
}