Update index.html

Author: Gmac4247

index.html

@@ -200,15 +200,14 @@
 },
 "dateCreated" :"2019-01-11",
 "datePublished":"2020-01-11",
-"dateModified" :"2025-08-08",
+"dateModified" :"2025-08-09",
 "description" : "Introducing the best-established and most accurate framework to calculate area and volume.",
 "disambiguatingDescription": "Exact, empirically grounded and rigorously proven formulas over the conventional approximations.",
 "headline":"Introducing the Core Geometric System ™",
 "image":[
      "geometry.jpeg",
      "trigonometry.png",
-	"equityFigure.jpg",
-	"cubeDissection.png"
+	"equityFigure.jpg"
 ],
 "inLanguage":"en-us",
 "isFamilyFriendly":"true",
@@ -502,12 +501,10 @@ <h1 style="font-size:160%;margin:7px">Introducing the Core Geometric System ™<
 <br>
 </div>
 <div>
-  <h2 style="font-size:160%;margin:7px;">How Accurate Are The Conventional Geometry Formulas?</h2>
-<br>
-<br>
-<p style="margin:12px;">Historically, Euclidean geometry has provided a framework for understanding and describing the physical world. It is based on axioms and postulates, leading to well-defined formulas for the calculation of areas and volumes of shapes such as circles and spheres.
+  <h2 style="font-size:160%;margin:7px;">Exact Geometry Formulas</h2>
 <br>
 <br>
+<p style="margin:12px;">
 Setting the square and the cube as the basis of the area and the volume calculation is well established and straightforward. Regardless of the shape of the measured object, the unit of measurement of the area is square units and the volume can be expressed in cubic units. 
 </p>
 </div>
@@ -2357,83 +2354,6 @@ <h6 style="font-size:160%;margin:7px;">Area of a regular polygon</h6>
     <mi>r</mi>
   </mrow>
 </math>
-<br>
-<br>
-<br>
-<br>
-<div>
-<p style="margin:12px;">The constant relationship between a circle's circumference and its diameter has captivated mathematicians for millennia. 
-While its approximate value of 3.14, commonly denoted by the Greek letter π, is widely recognized today, the historical development of this concept is less understood.
-Ancient civilizations grappled with this geometric challenge, employing various methods to approximate this ratio. 
-<br>
-<br>
-The Babylonians initially estimated it as 3, later they calculated with 3.125.
-<br>
-<br>
-A Greek mathematician is credited with refining these approximations through the method of inscribed and circumscribed polygons.
-<br>
-<br>
-His approach was that the ratio between the perimeter and the diameter of a circle can be estimated by comparing the circumference of the circle to the perimeters of an inscribed and a circumscribed polygon. 
-The polygons can be divided into triangles. The ratio between the legs of the triangles and their hypotenuses can be measured linearly.
-<br>
-That is where the pi divided by delta = 3.14 notation might originate from.
-<br>
-This method has several limitations. He tried to increase the accuracy by increasing the number of sides of the polygons. This approach cannot produce an accurate result. 
-<br>
-<br>
-Where the perimeter-based estimation went wrong: 
-<br>
-- aside of that it's just an approximation instead of an exact calculation - 
-<br>
-<br>
-The in- and circumscribed polygons method seems logical, but there's a catch. It's based on the assumption that the circle maximizes the area with a given circumference. That assumption is false. It's obviously true in the case of an isoperimetric triangle and a square, but it becomes less and less obvious with the increase of the number of the polygon's sides. Until eventually it is not even true. 
-<br>
-<br>
-Imagine a side of a polygon with a number of sides approaching infinity. 
-<br>
-<br>
-The angles between the side and the diagonals approach a right angle. They never reach a right angle as the diagonals converge towards the center.  If we relate the arc of a corresponding slice of an isoperimetric circle, the length of the arc equals the side in question. So the chord related to the arc is shorter than the side. If we want to place the arc with the chord so that it touches both diagonals, it has to be within the polygon. With the curvature of the arc becoming decreasingly distinctive, it doesn't bulge beyond the side. Eventually it will not even touch the side. Hence the polygon with the same number of sides, which circumscribed the circle is smaller, so its perimeter is shorter than the circle. 
-<br>
-<br>
-The perimeter of the circumscribed polygon that was believed to be an overestimate of the circumference was practically an underestimate of it. 
-<br>
-<br>
-Hence the value of the π lies between two underestimates.
-<br>
-<br>
-The same coefficient was used to calculate the ratio between the area and the squared radius of a circle.
-<br>
-<br>
-Despite these early advances, a precise, universally accepted value of this constant remained elusive for centuries. 
-<br>
-<br>
-Being uncertain about its numeric value and how to calculate it, it was comfortable to denote it by a sign in the equations.
-<br>
-<br>
-It was not until the 18th century that the symbol π, popularized by the mathematicians of the time, gained widespread acceptance.
-<br>
-<br>
-Several complex formulas were introduced by different mathematicians, aimed at more accurately estimating this ratio, based on a theoretical polygon with an infinite number of sides. 
-<br>
-<br>
-All of the above mentioned approximation methods have one thing in common. They are estimating the perimeters of polygons and do not account for the curved shape of the circle.
-<br>
-<br>
-Historical records suggest that a legislative process took place in 1897, Indiana, USA, known as House Bill 246, or Indiana Pi Act, aiming to replace the numeric value 3.14 by 3.2.
-<br>
-<br>
-Unfortunately, the exact details of the proposed method in the Indiana Pi Bill are somewhat obscure and have been interpreted differently by various accounts. 
-<br>
-<br>
-The π is a fundamental constant in the geometry of idealized circles and plays a crucial role in many mathematical theories. 
-<br>
-<br>
-My work, however, suggests that when we move from these idealizations to the measurement of real objects, a slightly different constant, 3.2 emerges as more relevant for accurately describing their properties. 
-<br>
-<br>
-By focusing on area relationships and direct comparisons between shapes, the above method emphasizes a more intuitive and potentially more fundamental understanding of geometric concepts.
-</p>
-</div>
 </div>
 <br>
 <br>
@@ -2498,34 +2418,6 @@ <h6 style="font-size:160%;margin:7px;">Area of a regular polygon</h6>
 <br>
 <p style="margin:12px;">The edge length of the cube, which has the same volume as the sphere, equals the square root of the area of the square that has the same area as the sphere's cross section.
 </p>
-<br>
-<br>
-<br>
-<div>
-<p style="margin:12px;">The " V = 4/3 × π × radius³ "  formula is widely used for the volume of a sphere, and it's a cornerstone of theoretical geometry. 
-<br>
-<br>
-However, my work focuses on the actual volume of physical spheres as determined through direct measurement. 
-<br>
-<br>
-My calculations and experiments have consistently indicated a different relationship, expressed by the formula V = ( √(3.2) × radius )³, which provides a more accurate result when dealing with real, physical entities. 
-<br>
-This formula isn't based on abstract geometric ideals alone but on tangible experiments where I've measured the volume of real spheres. 
-<br>
-These measurements have shown a systematic difference compared to the theoretical predictions based on the conventional formula, suggesting that the way we mathematically describe the volume of a sphere might need to be reconsidered when applied to physical objects. 
-<br>
-If you're trying to calculate the volume of a physical ball or sphere for a practical purpose – whether it's for a science experiment, engineering, or any other real-world application – my empirically derived formula offers a result that aligns more closely with what you would measure in the lab.
-<br>
-<br>
-The " 4/3 × π × radius³ " formula is a very rough approximation and can produce under- and overestimates. 
-<br>
-<br>
-The result of the ( √(3.2) × radius )³ formula is between the two.
-<br>
-<br>
-The " 4/3 × π × radius³ " formula is an underestimate. 
-</p>
-</div>
 </div>
 <br>
 <br>
@@ -2890,224 +2782,6 @@ <h6 style="font-size:160%;margin:7px;">Area of a regular polygon</h6>
 </mfrac>
 </mrow>
 </math>
-<br>
-<br>
-<br>
-<br>
-<div>
-<p style="margin:12px;">The commonly used base × height / 3 approximation for the volume of a cone was likely estimated based on two observations. 
-<br>
-<br>
-One is that the area of the mid-height cross section of a regular cone - of which's apex can be connected to the midpoint of the base with a perpendicular line - is exactly a quarter of a circumscribed solid's with the same base and height. 
-<br>
-That makes the ratio between the mid-height cross-sectional area of the cone, and the difference between the mid-height cross-sectional areas of the circumscribed solid and the cone 
-</p>
-<br>
-<br>
-<math style="margin:12px;" xmlns="http://www.w3.org/1998/Math/MathML" >
-<mrow>
-<mrow>
-<mo>(</mo>
-<mfrac>
-<mn>1</mn>
-<mn>4</mn>
-</mfrac>
-<mo>)</mo>
-</mrow>
-<mo>:</mo>
-<mrow>
-<mo>(</mo>
-<mn>1</mn>
-<mo>-</mo>
-<mrow>
-<mfrac>
-<mn>1</mn>
-<mn>4</mn>
-</mfrac>
-</mrow>
-<mo>)</mo>
-</mrow>
-<mo>=</mo>
-</mrow>
-</math>
-<br>
-<br>
-<math style="margin:12px;" xmlns="http://www.w3.org/1998/Math/MathML" >
-<mrow>
-<mrow>
-<mo>(</mo>
-<mfrac>
-<mn>1</mn>
-<mn>4</mn>
-</mfrac>
-<mo>)</mo>
-</mrow>
-<mo>:</mo>
-<mrow>
-<mo>(</mo>
-<mrow>
-<mfrac>
-<mn>4</mn>
-<mn>4</mn>
-</mfrac>
-</mrow>
-<mo>-</mo>
-<mrow>
-<mfrac>
-<mn>1</mn>
-<mn>4</mn>
-</mfrac>
-</mrow>
-<mo>)</mo>
-</mrow>
-<mo>=</mo>
-</mrow>
-</math>
-<br>
-<br>
-<math style="margin:12px;" xmlns="http://www.w3.org/1998/Math/MathML" >
-<mrow>
-<mrow>
-<mo>(</mo>
-<mfrac>
-<mn>1</mn>
-<mn>4</mn>
-</mfrac>
-<mo>)</mo>
-</mrow>
-<mo>:</mo>
-<mrow>
-<mo>(</mo>
-<mfrac>
-<mn>3</mn>
-<mn>4</mn>
-</mfrac>
-<mo>)</mo>
-</mrow>
-<mo>=</mo>
-</mrow>
-</math>
-<br>
-<br>
-<p style="margin:12px;">1 : 3 . 
-</p>
-<br>
-<br>
-<p style="margin:12px;">That is a logical consequence of its equilateral triangular cross-section.
-<br>
-<br>
-The same is true for regular pyramids. 
-<br>
-<br>
-Can this ratio can be generalized for the overall volume of any cone and pyramid? 
-<br>
-<br>
-No. Because it's not true in case of most other shapes.
-</p>
-<br>
-<br>
-<p style="margin:12px;">The other idea is the cube dissection. 
-<br>
-A common method aiming to prove the pyramid volume formula ( V = 1/3 × base × height ) involves dissecting a cube into three pyramids. Here’s how it’s typically presented:
-</p>
-<br>
-<div class="imgbox">
-    <img class="center-fit" src="cubeDissection.png" alt="Cube-dissection" id="dissection">
-</div>
-<br>
-<br>
-<p style="margin:12px;">Standard Cube Dissection Method:
-<br>
-<br>
-Take a cube with an edge length of ( e ).
-<br>
-<br>
-Volume of the cube: V = the cubic value of e.
-<br>
-<br>
-Imagine dividing the cube into three square pyramids, each with:
-<br>
-<br>
-- Base: One face of the cube, so the base area is the square value of e .
-<br>
-<br>
-- Height: The edge of the cube, ( e ), since the apex of each pyramid is the cube’s vertex opposite the base, depending on the dissection. 
-<br>
-<br>
-A common dissection:
-<br>
-<br>
-Choose one vertex of the cube as the apex.
-<br>
-<br>
-Form three pyramids, each with this apex and a base on one of the three faces adjacent to that vertex.
-<br>
-<br>
-Each pyramid has a base area of the square value of e, and height ( e ) (the distance from the apex to the base plane). 
-<br>
-<br>
-Volume of each pyramid: V(pyramid) = ( square value of e ) × e, divided by 3 = the cubic value of e divided by 3.
-<br>
-<br>
-Since there are three pyramids, their total volume is: 3 × ( ( cubic value of e ) divided by 3 ) = the cubic value of e.
-<br>
-<br>
-This equals the cube’s volume, suggesting the one third factor is correct.
-<br>
-<br>
-The Vertex Problem is a critical flaw in this dissection when applied to a real, physical cube:
-<br>
-<br>
-Vertex Assignment: 
-<br>
-<br>
-When we cut the cube into three pyramids sharing a common vertex as the apex, the geometry seems clean in theory. But if you physically slice the cube, you have to decide where that vertex belongs:
-<br>
-<br>
-The cube has 8 vertices, each pyramid has 5. Three pyramids have 3 × 5 = 15 in total.
-<br>
-<br>
-Each vertex is a point that can't be split into 3 points. The other way around, 3 points can't be merged into 1 without distortion. 
-<br>
-If we dissect the cube, we need to designate each shared vertex to be a part of either one pyramid, or another. 
-<br>
-<br>
-Consequence: 
-<br>
-<br>
-The volume of each pyramid is exactly a third of the cube, but with a base smaller than the square value of e, and height shorter than e.
-<br>
-<br>
-Their bases and heights are slightly adjusted due to the vertex assignment, undermining the proof’s simplicity.
-<br>
-<br>
-<br>
-If the solid pyramids'
-<br>
-<br>
-- base is the square value of e,
-<br>
-<br>
-and their 
-<br>
-<br>
-- height is e,
-<br>
-<br>
-then the volume of each pyramid has to be larger than 1/3 × base × height, because 3 such pyramids can't form a cube with the same edge length, because their vertices and faces can't occupy the same space simultaneously.
-<br>
-<br>
-The vertices are the most obvious examples, but the same is true for the edges, the diagonals and the inner faces. 
-<br>
-<br>
-Applied correctly, the cube dissection proves that the volume of a cone or a pyramid has to be larger than base × height / 3.
-<br>
-<br>
-The fact that the vertices of the 3 pyramids can't be merged into a single point without distortion proves that the so-called "calculus-based proofs" of the conventional formula are invalid. 
-<br>
-Also it's not just about the vertices, but the edges and the inner faces, too.
-</p>
-</div>
 </div>
 <br>
 <br>