|
179 | 179 | }, |
180 | 180 | "dateCreated" :"2019-01-11", |
181 | 181 | "datePublished":"2020-01-11", |
182 | | -"dateModified" :"2025-05-24", |
183 | | -"description" :"Introducing the best-established and most accurate framework to calculate area and volume.", |
184 | | -"disambiguatingDescription": "Providing precise formulas based on empirical considerations and fundamental relationships instead of the conventional approximations.", |
| 182 | +"dateModified" :"2025-05-27", |
| 183 | +"description" : "Introducing the best-established and most accurate framework to calculate area and volume.", |
| 184 | +"disambiguatingDescription": "Exact, empirically grounded and rigorously proven formulas over the conventional approximations.", |
185 | 185 | "headline":"Exact geometry", |
186 | 186 | "inLanguage":"en-us", |
187 | 187 | "image":[ |
|
197 | 197 | "mainEntity" : { |
198 | 198 | "@type": ["MathSolver", "LearningResource"], |
199 | 199 | "name" : "Core Geometric System ™", |
| 200 | +"description":"The best-established, empirically grounded, rigorously proven and most accurate framework." |
| 201 | + "disambiguatingDescription": "Exact formulas over the traditional approximations. More accurate for real-world applications.", |
| 202 | +"keywords":"Exact Formulas, Area of a Circle, Circumference of a Circle, Volume of a Sphere, Volume of a Cone, Volume of a Pyramid, Volume of a Tetrahedron, Volume of a Frustum", |
200 | 203 | "inLanguage":"en-us", |
201 | 204 | "url": "https://basic-geometry.github.io/", |
202 | 205 | "usageInfo":"Calculate area and volume with enhanced accuracy using the Core Geometric System ™. This innovative framework provides a practical alternative to traditional methods, rooted in comparative geometry and scaling principles. Learn exact formulas for circles (A = 3.2r^2, C = 6.4r), spheres (V = (√(3.2)r)^3), cones, and more, with applications in engineering, computer graphics, and scientific research.", |
|
227 | 230 | { |
228 | 231 | "@type": "SolveMathAction", |
229 | 232 | "name": "Area of a circle", |
230 | | -"description": "Calculates the exact area of a circle using a refined approach that replaces traditional π-based approximations. This method is based on direct shape relationships, ensuring greater accuracy in real-world measurements.", |
231 | | - "target": "https://basic-geometry.github.io/", |
| 233 | +""description": "The exact area of a circle based on direct comparison with a square.", |
| 234 | + "disambiguatingDescription": "Replaces traditional π-based approximations ensuring greater accuracy in real-world measurements.", |
| 235 | + "keywords":"Exact Area of a Circle, Direct Comparison, Quadrants Method, Rigorously Proven", |
| 236 | + "target": "https://basic-geometry.github.io/", |
232 | 237 | "mathExpression-input": "r=5 A=?", |
233 | 238 | "mathExpression-output": "angle of rotation / 360 * 3.2 * Math.pow(radius, 2)", |
234 | 239 | "image": "areaOfACircle.jpg", |
|
238 | 243 | { |
239 | 244 | "@type": "SolveMathAction", |
240 | 245 | "name": "Area of a circle segment", |
241 | | - "description": "Calculates the area of a circle segment based on its radius and the height of the segment", |
242 | | - "target": "https://basic-geometry.github.io/", |
| 246 | +"description": "The exact area of a circle segment by subtracting a triangle from a circle slice.", |
| 247 | + "disambiguatingDescription": "Equivalent to the conventional method, but relies on trigonometric functions.", |
| 248 | + "keywords":"Exact Area of a Circle Segment, Rigorously Proven", |
| 249 | + "target": "https://basic-geometry.github.io/", |
243 | 250 | "mathExpression-input": "r=5 h=2 A=?", |
244 | 251 | "mathExpression-output": "Math.acos((radius-segmentHeight)/radius)*Math.pow(radius, 2)-Math.sin(Math.acos((radius-segmentHeight)/radius))*(radius-segmentHeight)*radius", |
245 | 252 | "image": "circleSegment.jpg", |
|
249 | 256 | { |
250 | 257 | "@type": "SolveMathAction", |
251 | 258 | "name": "Circumference of a circle", |
252 | | - "description": "Calculates the exact circumference of a circle using a refined approach that replaces traditional π-based approximations. This method is based on direct shape relationships, ensuring greater accuracy in real-world measurements.", |
| 259 | +"description": "The exact circumference of a circle using a refined approach that replaces traditional π-based approximations. This method is based on direct shape relationships, ensuring greater accuracy in real-world measurements.", |
| 260 | +"disambiguatingDescription": "Replaces traditional π-based approximations ensuring greater accuracy in real-world measurements.", |
| 261 | + "keywords":"Circumference of a Circle, Algebraic Derivation from the Area, Rigorously Proven", |
253 | 262 | "target": "https://basic-geometry.github.io/", |
254 | 263 | "mathExpression-input": "r=5 C=?", |
255 | 264 | "mathExpression-output": "angle of rotation / 360 * 6.4 * radius", |
|
260 | 269 | { |
261 | 270 | "@type": "SolveMathAction", |
262 | 271 | "name": "Volume of a sphere", |
263 | | - "description": "Calculates the exact volume of a sphere by directly comparing it to a cube. This method is based on direct shape relationships, ensuring greater accuracy in real-world measurements.", |
264 | | - "target": "https://basic-geometry.github.io/", |
| 272 | + "description": "The exact volume of a sphere by directly comparing it to a cube. Direct shape relationships ensure greater accuracy in real-world measurements.", |
| 273 | + "disambiguatingDescription": "More accurate than the traditional exhaustion method based formula which is a very rough underestimate. |
| 274 | + "keywords" : "Direct Comparison, Exact Volume, Rigorously proven", |
| 275 | + "target": "https://basic-geometry.github.io/", |
265 | 276 | "mathExpression-input": "r=3 V=?", |
266 | 277 | "mathExpression-output": "angle of rotation / 360 * Math.pow((Math.sqrt(3.2) * radius), 3)", |
267 | 278 | "image": "sphereAndCubeMarkup.jpeg", |
|
271 | 282 | { |
272 | 283 | "@type": "SolveMathAction", |
273 | 284 | "name": "Volume of a spherical cap", |
274 | | - "description": "Calculates the volume of a spherical cap based on the radius of the sphere and the cap.", |
275 | | - "target": "https://basic-geometry.github.io/", |
| 285 | + "description": "The volume of a spherical cap based on the radius of the sphere and the cap.", |
| 286 | + "disambiguatingDescription": "More accurate than the conventional formula ", |
| 287 | + "keywords":"Spherical cap volume", |
| 288 | + "target": "https://basic-geometry.github.io/", |
276 | 289 | "mathExpression-input": "r1=5 r2=3 V=?", |
277 | 290 | "mathExpression-output": "1.6 * Math.pow(sphereSliceBottomRadius, 2) * Math.sqrt(3.2) * (1 - Math.sin(Math.acos(sphereSliceBottomRadius / sphereRadius)))", |
278 | 291 | "image": "sphericalCap.jpg", |
|
284 | 297 | "@type": "SolveMathAction", |
285 | 298 | "target": "https://basic-geometry.github.io/", |
286 | 299 | "name": "Volume of a cone", |
287 | | - "description": "Calculates the exact volume of a cone by comparing the volume of a quarter cone to an octant of a sphere with an equal radius. This method is based on direct shape relationships, ensuring greater accuracy in real-world measurements.", |
| 300 | + "description": "The exact volume of a cone by comparing the volume of a quarter cone to an octant sphere with an equal radius.", |
| 301 | + "disambiguatingDescription": "Instead of the inaccurate base×height/3 approximation, direct shape relationships ensure greater accuracy in real-world measurements. |
| 302 | + "keywords":"Volume of a cone, Octant sphere comparison", |
288 | 303 | "mathExpression-input": "r=5 H=3 V=?", |
289 | 304 | "mathExpression-output": "angleOfRotation / 360 * 3.2 * Math.pow(radius, 2) * height / Math.sqrt(8)", |
290 | 305 | "image": [ |
|
299 | 314 | { |
300 | 315 | "@type": "SolveMathAction", |
301 | 316 | "name": "Volume of a frustum cone", |
302 | | - "description": "Calculates the exact volume of a frustum cone based on its top and bottom diameter and height", |
303 | | - "target": "https://basic-geometry.github.io/", |
| 317 | + "description": "The exact volume of a frustum cone based on its top and bottom diameter and height", |
| 318 | + "disambiguatingDescription": "The formula subtracts the missing tip from a theoretical full cone", |
| 319 | + "keywords": "Frustum cone volume, universal subtraction method", |
| 320 | + "target": "https://basic-geometry.github.io/", |
304 | 321 | "mathExpression-input": "d1=5 d2=2 h=3 V=?", |
305 | 322 | "mathExpression-output": "frustumHeight * (4 / 5 * Math.pow(bottomDiameter, 2) * (1 / (1 - topDiameter / bottomDiameter)) - 4 / 5 * Math.pow(topDiameter, 2) * (1 / (1 - topDiameter / bottomDiameter) - 1)) / Math.sqrt(8)", |
306 | 323 | "image": "frustumOfConeMarkup.png", |
|
310 | 327 | { |
311 | 328 | "@type": "SolveMathAction", |
312 | 329 | "name":"Surface area of a cone", |
313 | | - "description": "Calculates the exact surface area of a cone based on its radius and height", |
314 | | - "target": "https://basic-geometry.github.io/", |
| 330 | + "description": "The exact surface area of a cone based on its radius and height.", |
| 331 | + "disambiguatingDescription": "Equivalent to the conventional formula, but relies on the real height." |
| 332 | + "keywords": "Surface area of a cone based on its radius and height.", |
| 333 | + "target": "https://basic-geometry.github.io/", |
315 | 334 | "mathExpression-input": "r=5 H=3 A=?", |
316 | 335 | "mathExpression-output": "3.2 * (Math.pow(radius, 2) + (Math.pow(radius, 2) + Math.pow(height, 2)) * (radius / Math.sqrt(Math.pow(radius, 2) + Math.pow(height, 2))))", |
317 | 336 | "image": "coneMarkup.jpeg", |
|
321 | 340 | { |
322 | 341 | "@type": "SolveMathAction", |
323 | 342 | "name": "Volume of a pyramid", |
324 | | - "description": "Calculates the exact volume of a pyramid based on the bottom area and the height of the pyramid", |
325 | | - "target": "https://basic-geometry.github.io/", |
| 343 | + "description": "The exact volume of a pyramid based on its bottom area and height using the coefficient of the volume of a cone", |
| 344 | + "disambiguatingDescription": "Instead of the inaccurate base×height/3 approximation, direct shape relationships ensure greater accuracy in real-world measurements. |
| 345 | + "keywords":"Pyramid volume, rigorously proven", |
| 346 | + "target": "https://basic-geometry.github.io/", |
326 | 347 | "mathExpression-input": "A=5 H=3 V=?", |
327 | 348 | "mathExpression-output": "baseArea * height / Math.sqrt(8)", |
328 | 349 | "image": [ |
|
335 | 356 | { |
336 | 357 | "@type": "SolveMathAction", |
337 | 358 | "name": "Volume of a frustum pyramid", |
338 | | - "description": "Calculates the exact volume of a frustum pyramid based on its top and bottom edge length and height", |
339 | | - "target": "https://basic-geometry.github.io/", |
| 359 | + "description": "The exact volume of a frustum pyramid based on its top and bottom base area and height", |
| 360 | + "disambiguatingDescription": "The formula subtracts the missing tip from a theoretical full pyramid. Universally applicable", |
| 361 | + "keywords": "Frustum pyramid volume, universal subtraction method, rigorously proven", |
| 362 | + "target": "https://basic-geometry.github.io/", |
340 | 363 | "mathExpression-input": "a=5 b=3 H=2 V=?", |
341 | 364 | "mathExpression-output": "frustumHeight * (Math.pow(bottomEdge, 2) * (1 / (1 - topEdge / bottomEdge)) - Math.pow(topEdge, 2) * (1 / (1 - topEdge / bottomEdge) - 1)) / Math.sqrt(8)", |
342 | 365 | "image": "frustumOfPyramidMarkup.png", |
|
346 | 369 | { |
347 | 370 | "@type": "SolveMathAction", |
348 | 371 | "name": "Volume of a tetrahedron", |
349 | | - "description": "Calculates the exact volume of a tetrahedron based on its edge length", |
350 | | - "target": "https://basic-geometry.github.io/", |
| 372 | + "description": "The exact volume of a tetrahedron based on its edge length", |
| 373 | + "disambiguatingDescription": "Based on the base×height/√8 formula, instead of the inaccurate conventional coefficient", |
| 374 | +"keywords": "tetrahedron volume, rigorously proven", |
| 375 | + "target": "https://basic-geometry.github.io/", |
351 | 376 | "mathExpression-input": "a=5 V=?", |
352 | 377 | "mathExpression-output": "Math.pow(edge, 3) / 8", |
353 | 378 | "image": "tetrahedronMarkup.jpeg", |
|
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