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MaxCounters
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89 lines (61 loc) · 2.28 KB
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You are given N counters, initially set to 0, and you have two possible operations on them:
increase(X) − counter X is increased by 1,
max counter − all counters are set to the maximum value of any counter.
A non-empty array A of M integers is given. This array represents consecutive operations:
if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X),
if A[K] = N + 1 then operation K is max counter.
For example, given integer N = 5 and array A such that:
A[0] = 3
A[1] = 4
A[2] = 4
A[3] = 6
A[4] = 1
A[5] = 4
A[6] = 4
the values of the counters after each consecutive operation will be:
(0, 0, 1, 0, 0)
(0, 0, 1, 1, 0)
(0, 0, 1, 2, 0)
(2, 2, 2, 2, 2)
(3, 2, 2, 2, 2)
(3, 2, 2, 3, 2)
(3, 2, 2, 4, 2)
The goal is to calculate the value of every counter after all operations.
Write a function:
function solution($N, $A);
that, given an integer N and a non-empty array A consisting of M integers, returns a sequence of integers representing the values of the counters.
Result array should be returned as an array of integers.
For example, given:
A[0] = 3
A[1] = 4
A[2] = 4
A[3] = 6
A[4] = 1
A[5] = 4
A[6] = 4
the function should return [3, 2, 2, 4, 2], as explained above.
Write an efficient algorithm for the following assumptions:
N and M are integers within the range [1..100,000];
each element of array A is an integer within the range [1..N + 1].
************************************** SOLUTION **********************************************
function solution($N, $A) {
if (empty($A)) {
return 0;
}
$arrayASize = sizeof($A);
if ((is_integer($N) && ($N >= 1 && $N <= 100000)) &&
($arrayASize >= 1 && $arrayASize <= 100000)) {
$counters = array_fill(0, $N, 0);
foreach ($A as $key => $value) {
if (is_integer($value) && ($value >= 1 && $value <= $N + 1)) {
if ($value >= 1 && $value <= $N) {
$counters[$value - 1] += 1;
}
if ($value == $N + 1) {
$counters = array_fill(0, sizeof($counters), max($counters));
}
}
}
}
return $counters;
}