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Valid Parentheses.py
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51 lines (49 loc) · 1.22 KB
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# https://leetcode.com/problems/valid-parentheses/
# Hak Soo Kim
# 2/28/2021
class Solution(object):
def isValid(self, s):
stack = []
for i in s:
if (i == '(' or i == '{' or i == '['):
stack.append(i)
elif (i == ')'):
if (stack == [] or stack.pop() != '('):
return False
elif (i == '}'):
if (stack == [] or stack.pop() != '{'):
return False
elif (i == ']'):
if (stack == [] or stack.pop() != '['):
return False
if (stack == []):
return True
return False
"""
:type s: str
:rtype: bool
"""
# Given a string s containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.
#
# An input string is valid if:
#
# Open brackets must be closed by the same type of brackets.
# Open brackets must be closed in the correct order.
#
# Example 1:
#
# Input: s = "()"
# Output: true
# Example 2:
#
# Input: s = "()[]{}"
# Output: true
# Example 3:
#
# Input: s = "(]"
# Output: false
#
# Constraints:
#
# 1 <= s.length <= 104
# s consists of parentheses only '()[]{}'.