[Bug] Type checking with `typeof` directly always results in `true` expressions

[KawaiiBakemono]

Is there an existing issue for this?

• I have searched the existing issues

I am following the documentation's guide

• I have read the documentation

This issue exists in the latest version

• I am using the latest version

Current Behavior

Type checking always results in true expressions due to improper brace insertion in the code generator. For example:

var x: num = 123;

if (typeof(x) != num) {
    print("This will always print!");
}

Output:

This will always print!

Finished execution with exit code 0.

Expected Behavior

Unequal expressions should result in false.

var x: num = 123;

if (typeof(x) != num) {
    print("This should never print");
}

Steps To Reproduce

1. Define a variable of any type (ex. var x: num = 1;)
2. Create an if statement to check if the typeof the previously defined variable is not equal to the type it was defined as (ex. if (x != num) { ... })

Workarounds

Currently, to have functional type checking, you must creating a variable that is solely the typeof the variable you are attempting to check (in this case a num), like so:

var x: num = 123;
var checker: type = typeof(num);

if (x != checker) {
    print("Works as expected.");
}

Environment

• Kipper: 0.12.1
• Environment: Vivaldi 7.6.3797.56 (Playground)
• Operating System: Arch Linux