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100_Same_Tree
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75 lines (63 loc) · 1.97 KB
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Leetcode 100: Same Tree
Detailed video explanation of Recursive and Iterative Approach: https://youtu.be/5qj18l76xy4
C++:
====
Recursive:
----------
bool isSameTree(TreeNode* p, TreeNode* q) {
if(!p && !q) return true;
if(!p || !q) return false;
if(p->val != q->val) return false;
return isSameTree(p->left, q->left) && isSameTree(p->right, q->right);
}
Iterative:
----------
class Solution {
bool areEqual(TreeNode* p, TreeNode* q){
if(!p && !q) return true;
if(!p || !q) return false;
if(p->val != q->val) return false;
return true;
}
public:
bool isSameTree(TreeNode* p, TreeNode* q) {
if(!areEqual(p, q)) return false;
queue<TreeNode*> Q1, Q2;
Q1.push(p);
Q2.push(q);
while(!Q1.empty()){
TreeNode* n1 = Q1.front();
Q1.pop();
TreeNode* n2 = Q2.front();
Q2.pop();
if(!areEqual(n1, n2)) return false;
if(n1){
if(!areEqual(n1->left, n2->left)) return false;
if(n1->left){
Q1.push(n1->left);
Q2.push(n2->left);
}
if(!areEqual(n1->right, n2->right)) return false;
if(n1->right){
Q1.push(n1->right);
Q2.push(n2->right);
}
}
}
return true;
}
Java:
=====
public boolean isSameTree(TreeNode p, TreeNode q) {
if(p == null && q == null) return true;
if(p == null || q == null) return false;
if(p.val != q.val) return false;
return isSameTree(p.left, q.left) && isSameTree(p.right, q.right);
}
Python3:
========
def isSameTree(self, p: TreeNode, q: TreeNode) -> bool:
if p == None and q == None: return True
if p == None or q == None: return False
if p.val != q.val: return False
return self.isSameTree(p.left, q.left) and self.isSameTree(p.right, q.right)