.: wildcard
+: 1..⏦
*: 0..⏦
?: 0..1
|: or
\u: Unicode character by using hexadecimal representation
[characher_group]: any in characher_group
[^characher_group]: not in characher_group
$: at the end of the line
^: at the beginning of the line
(): make them a group
// I wrote it only for self-help...
func BasicWithRegex() -> String {
let returnString : String
let questionsFromGirlfriend = "到底為什麼不先講一聲"
switch questionsFromGirlfriend {
case let x where x.contains(/.*(\u9910\u5403)+[^\u55CE]*(\u597D)?(\u55CE)$/):
// ..餐吃..(好)嗎
returnString = "好啊"
case let y where y.contains(/.*(\u4F60\u6703)+[^\u55CE]*(\u55CE)$/):
// ..你會..嗎
let yy = GetSubstring(words: y)
returnString = "那\(yy)？"
case let z where z.contains(/.*(\u662F\u4E0D\u662F)+.*/):
// ..是不是..
returnString = "那你是不是很喜歡我 >///<"
case let a where a.contains(/.*(\u5230\u5E95\u70BA\u4EC0\u9EBC|\u70BA\u4EC0\u9EBC\u4E0D)+.*/):
// ..到底為什麼.. || ..為什麼不..
returnString = "我也不知道為什麼 Q^Q"
case let b where b.contains(/.*(\u4F60\u5230\u5E95\u5728)+.*/):
// ..你到底在..
returnString = "對不起 orz"
default:
returnString = "你還是一樣漂亮！"
}
return returnString
}
// just put it here in case you wanna know...
func GetSubstring(words : String) -> String {
var substring = words
while true {
if substring[substring.startIndex] == "你" && substring[substring.index(after: substring.startIndex)] == "會" {
return substring
} else {
substring.removeFirst(1)
}
}
}Since/If our/your native language is traditional Chinese, BasicWithRegex() can be rewritten as follows:
func RegexWithoutUnicode() -> String {
let returnString : String
let questionsFromGirlfriend = "餐吃嗎嗎"
switch questionsFromGirlfriend {
case let x where x.contains(/.*(餐吃)+[^嗎]*(好)?(嗎)$/):
// ..餐吃..(好)嗎
returnString = "好啊"
case let y where y.contains(/.*(你會)+[^嗎]*(嗎)$/):
// ..你會..嗎
let yy = GetSubstring(words: y)
returnString = "那\(yy)？"
case let z where z.contains(/.*(是不是)+.*/):
// ..是不是..
returnString = "那你是不是很喜歡我 >///<"
case let a where a.contains(/.*(到底為什麼|為什麼不)+.*/):
// ..到底為什麼.. || ..為什麼不..
returnString = "我也不知道為什麼 Q^Q"
case let b where b.contains(/.*(你到底在)+.*/):
// ..你到底在..
returnString = "對不起 orz"
default:
returnString = "你還是一樣漂亮！"
}
return returnString
}- Regular Expression Language - Quick Reference