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package leetcode_1To300;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _368_LargestDivisibleSubset {
/**
* 368. Largest Divisible Subset
* Given a set of distinct positive integers, find the largest subset such that every pair (Si, Sj)
* of elements in this subset satisfies: Si % Sj = 0 or Sj % Si = 0.
If there are multiple solutions, return any subset is fine.
Example 1:
nums: [1,2,3]
Result: [1,2] (of course, [1,3] will also be ok)
Example 2:
nums: [1,2,4,8]
Result: [1,2,4,8]
1 2 4 6 8
1 2 4 6 8
pre : -1 0 1 1 2
count: 1 2 3 3 4
Arrays.sort()
count[]
pre[] : index[]
int index(4) max(4)
a % b == 0
b % c == 0
a % c == 0
pre
time : O(n^2)
space : O(n)
* @param nums
* @return
*/
public List<Integer> largestDivisibleSubset(int[] nums) {
if (nums == null || nums.length == 0) return new ArrayList<>();
Arrays.sort(nums);
int[] count = new int[nums.length];
int[] pre = new int[nums.length];
int max = 0, index = -1;
for (int i = 0; i < nums.length; i++) {
count[i] = 1;
pre[i] = -1;
for (int j = i - 1; j >= 0; j--) {
if (nums[i] % nums[j] == 0) {
if (1 + count[j] > count[i]) {
count[i] = count[j] + 1;
pre[i] = j;
}
}
if (count[i] > max) {
max = count[i];
index = i;
}
}
}
List<Integer> res = new ArrayList<>();
while (index != -1) {
res.add(nums[index]);
index = pre[index];
}
return res;
}
}