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_376_WiggleSubsequence.java
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package leetcode_1To300;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _376_WiggleSubsequence {
/**
* 376. Wiggle Subsequence
* Examples:
Input: [1,7,4,9,2,5]
Output: 6
The entire sequence is a wiggle sequence.
Input: [1,17,5,10,13,15,10,5,16,8]
Output: 7
There are several subsequences that achieve this length. One is [1,17,10,13,10,16,8].
Input: [1,2,3,4,5,6,7,8,9]
Output: 2
dp up[] down[]
Input: [1,7,4,9,2,5]
up[1,2,2]
down[1,1,3]
time : O(n)
space : O(n) / O(1)
* @param nums
* @return
*/
public int wiggleMaxLength(int[] nums) {
if (nums.length == 0) return 0;
int[] up = new int[nums.length];
int[] down = new int[nums.length];
up[0] = 1;
down[0] = 1;
for (int i = 1; i < nums.length; i++) {
if (nums[i] > nums[i - 1]) {
up[i] = down[i - 1] + 1;
down[i] = down[i - 1];
} else if (nums[i] < nums[ i - 1]) {
down[i] = up[i - 1] + 1;
up[i] = up[i - 1];
} else {
down[i] = down[i - 1];
up[i] = up[i - 1];
}
}
return Math.max(down[nums.length - 1], up[nums.length - 1]);
}
public int wiggleMaxLength2(int[] nums) {
if (nums.length == 0) return 0;
int up = 1, down = 1;
for (int i = 1; i < nums.length; i++) {
if (nums[i] > nums[i - 1]) {
up = down + 1;
} else if (nums[i] < nums[i - 1]) {
down = up + 1;
}
}
return Math.max(up, down);
}
}