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_391_PerfectRectangle.java
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package leetcode_1To300;
import java.util.HashSet;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _391_PerfectRectangle {
/**
* 391. Perfect Rectangle
* time : O(n)
* space : O(n)
* @param rectangles
* @return
*/
public boolean isRectangleCover(int[][] rectangles) {
if (rectangles.length == 0 || rectangles[0].length == 0) return false;
int x1 = Integer.MAX_VALUE;
int x2 = Integer.MIN_VALUE;
int y1 = Integer.MAX_VALUE;
int y2 = Integer.MIN_VALUE;
HashSet<String> set = new HashSet<>();
int area = 0;
for (int[] rect : rectangles) {
x1 = Math.min(rect[0], x1);
y1 = Math.min(rect[1], y1);
x2 = Math.max(rect[2], x2);
y2 = Math.max(rect[3], y2);
area += (rect[2] - rect[0]) * (rect[3] - rect[1]);
String s1 = rect[0] + " " + rect[1];
String s2 = rect[0] + " " + rect[3];
String s3 = rect[2] + " " + rect[3];
String s4 = rect[2] + " " + rect[1];
if (!set.add(s1)) set.remove(s1);
if (!set.add(s2)) set.remove(s2);
if (!set.add(s3)) set.remove(s3);
if (!set.add(s4)) set.remove(s4);
}
if (!set.contains(x1 + " " + y1) || !set.contains(x1 + " " + y2)
|| !set.contains(x2 + " " + y1) || !set.contains(x2 + " " + y2) || set.size() != 4) {
return false;
}
return area == (x2 - x1) * (y2 - y1);
}
}