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logicalORofTwoBinaryGridsRepresentedasQuad-Trees.cpp
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64 lines (59 loc) · 1.82 KB
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// Source: https://leetcode.com/problems/logical-or-of-two-binary-grids-represented-as-quad-trees/
// Author: Miao Zhang
// Date: 2021-02-22
/*
// Definition for a QuadTree node.
class Node {
public:
bool val;
bool isLeaf;
Node* topLeft;
Node* topRight;
Node* bottomLeft;
Node* bottomRight;
Node() {
val = false;
isLeaf = false;
topLeft = NULL;
topRight = NULL;
bottomLeft = NULL;
bottomRight = NULL;
}
Node(bool _val, bool _isLeaf) {
val = _val;
isLeaf = _isLeaf;
topLeft = NULL;
topRight = NULL;
bottomLeft = NULL;
bottomRight = NULL;
}
Node(bool _val, bool _isLeaf, Node* _topLeft, Node* _topRight, Node* _bottomLeft, Node* _bottomRight) {
val = _val;
isLeaf = _isLeaf;
topLeft = _topLeft;
topRight = _topRight;
bottomLeft = _bottomLeft;
bottomRight = _bottomRight;
}
};
*/
class Solution {
public:
Node* intersect(Node* quadTree1, Node* quadTree2) {
if (quadTree1->isLeaf) {
return quadTree1->val ? quadTree1 : quadTree2;
}
if (quadTree2->isLeaf) {
return quadTree2->val ? quadTree2 : quadTree1;
}
Node* tl = intersect(quadTree1->topLeft, quadTree2->topLeft);
Node *tr = intersect(quadTree1->topRight, quadTree2->topRight);
Node *bl = intersect(quadTree1->bottomLeft, quadTree2->bottomLeft);
Node *br = intersect(quadTree1->bottomRight, quadTree2->bottomRight);
if (tl->val == tr->val && tl->val == bl->val && tl->val == br->val && tl->isLeaf && tr->isLeaf && bl->isLeaf && br->isLeaf) {
return new Node(tl->val, true, NULL, NULL, NULL, NULL);
} else {
return new Node(false, false, tl, tr, bl, br);
}
}
};