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0073__set_matrix_zeroes.py
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81 lines (60 loc) · 2.26 KB
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"""
LeetCode: https://leetcode.com/problems/set-matrix-zeroes/
Given an m x n integer matrix matrix, if an element is 0, set its entire row and column to 0's.
You must do it in place.
## Example 1
Input: matrix = [[1,1,1],[1,0,1],[1,1,1]]
Output: [[1,0,1],[0,0,0],[1,0,1]]
## Example 2
Input: matrix = [[0,1,2,0],[3,4,5,2],[1,3,1,5]]
Output: [[0,0,0,0],[0,4,5,0],[0,3,1,0]]
## Constraints
* m == matrix.length
* n == matrix[0].length
* 1 <= m, n <= 200
* -2^31 <= matrix[i][j] <= 2^31 - 1
## Follow up
* A straightforward solution using O(mn) space is probably a bad idea.
* A simple improvement uses O(m + n) space, but still not the best solution.
* Could you devise a constant space solution?
"""
from typing import List
from unittest import TestCase
class Solution(TestCase):
def test_example_1(self):
matrix = [[1, 1, 1], [1, 0, 1], [1, 1, 1]]
expected = [[1, 0, 1], [0, 0, 0], [1, 0, 1]]
self.setZeroes(matrix)
self.assertEqual(expected, matrix)
def test_example_2(self):
matrix = [[0, 1, 2, 0], [3, 4, 5, 2], [1, 3, 1, 5]]
expected = [[0, 0, 0, 0], [0, 4, 5, 0], [0, 3, 1, 0]]
self.setZeroes(matrix)
self.assertEqual(expected, matrix)
def test_case_6(self):
matrix = [[0], [1]]
expected = [[0], [0]]
self.setZeroes(matrix)
self.assertEqual(expected, matrix)
def setZeroes(self, matrix: List[List[int]]) -> None:
"""
Do not return anything, modify matrix in-place instead.
"""
should_mark_first_row = False
for col in range(len(matrix[0])):
if matrix[0][col] == 0:
should_mark_first_row = True
for row in range(1, len(matrix)):
for col in range(len(matrix[row])):
if matrix[row][col] == 0:
matrix[row][0] = 0
matrix[0][col] = 0
# now mark everything, but the first row
for row in range(1, len(matrix)):
for col in range(len(matrix[row]) - 1, -1, -1):
if matrix[0][col] == 0 or matrix[row][0] == 0:
matrix[row][col] = 0
# mark first row if necessary
if should_mark_first_row:
for col in range(len(matrix[0])):
matrix[0][col] = 0