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"""
1347. Minimum Number of Steps to Make Two Strings Anagram
You are given two strings of the same length s and t. In one step you can choose any character of t and replace it with another character.
Return the minimum number of steps to make t an anagram of s.
An Anagram of a string is a string that contains the same characters with a different (or the same) ordering.
Example
1:
Input: s = "bab", t = "aba"
Output: 1
Explanation: Replace
the
first
'a' in t
with b, t = "bba" which is anagram of s.
Example
2:
Input: s = "leetcode", t = "practice"
Output: 5
Explanation: Replace
'p', 'r', 'a', 'i' and 'c'
from t
with proper characters to make t anagram of s.
Example
3:
Input: s = "anagram", t = "mangaar"
Output: 0
Explanation: "anagram" and "mangaar"
are
anagrams.
Constraints:
1 <= s.length <= 5 * 104
s.length == t.length
s and t consist of lowercase English letters only.
"""
class Solution:
def minSteps(self, s: str, t: str) -> int:
# initialize two arrays to store the frequency of each character in s and t
count_s = [0] * 26
count_t = [0] * 26
# loop through the characters in s and increment the corresponding frequency in count_s
for char in s:
# subtract the ASCII value of 'a' from the ASCII value of the character to get the index of the array
count_s[ord(char) - ord('a')] += 1
# loop through the characters in t and increment the corresponding frequency in count_t
for char in t:
# subtract the ASCII value of 'a' from the ASCII value of the character to get the index of the array
count_t[ord(char) - ord('a')] += 1
# initialize the number of steps to 0
steps = 0
# loop through the 26 possible characters
for i in range(26):
# add the absolute difference between the frequencies in count_s and count_t to the number of steps
steps += abs(count_s[i] - count_t[i])
# return the number of steps divided by 2, since each step can change two characters
return steps // 2