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Frequentvalues.cpp
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151 lines (119 loc) · 4.11 KB
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#include <bits/stdc++.h>
#include <iostream>
#include <vector>
#include <set>
#include <map>
#include <iomanip>
#include <algorithm>
using namespace std;
#define DESLOQUE 100000
typedef vector<int> vi;
class SegmentTree { // OOP style
private:
int n; // n = (int)A.size()
vi A, st, lazy; // the arrays
int l(int p) { return p<<1; } // go to left child
int r(int p) { return (p<<1)+1; } // go to right child
int conquer(int a, int b) {
if (a == -1) return b; // corner case
if (b == -1) return a;
return min(a, b); // RMQ
}
void build(int p, int L, int R) { // O(n)
if (L == R)
st[p] = A[L]; // base case
else {
int m = (L+R)/2;
build(l(p), L , m);
build(r(p), m+1, R);
st[p] = conquer(st[l(p)], st[r(p)]);
}
}
void propagate(int p, int L, int R) {
if (lazy[p] != -1) { // has a lazy flag
st[p] = lazy[p]; // [L..R] has same value
if (L != R) // not a leaf
lazy[l(p)] = lazy[r(p)] = lazy[p]; // propagate downwards
else // L == R, a single index
A[L] = lazy[p]; // time to update this
lazy[p] = -1; // erase lazy flag
}
}
int RMQ(int p, int L, int R, int i, int j) { // O(log n)
propagate(p, L, R); // lazy propagation
if (i > j) return -1; // infeasible
if ((L >= i) && (R <= j)) return st[p]; // found the segment
int m = (L+R)/2;
return conquer(RMQ(l(p), L , m, i , min(m, j)),
RMQ(r(p), m+1, R, max(i, m+1), j ));
}
void update(int p, int L, int R, int i, int j, int val) { // O(log n)
propagate(p, L, R); // lazy propagation
if (i > j) return;
if ((L >= i) && (R <= j)) { // found the segment
lazy[p] = val; // update this
propagate(p, L, R); // lazy propagation
}
else {
int m = (L+R)/2;
update(l(p), L , m, i , min(m, j), val);
update(r(p), m+1, R, max(i, m+1), j , val);
int lsubtree = (lazy[l(p)] != -1) ? lazy[l(p)] : st[l(p)];
int rsubtree = (lazy[r(p)] != -1) ? lazy[r(p)] : st[r(p)];
st[p] = (lsubtree <= rsubtree) ? st[l(p)] : st[r(p)];
}
}
public:
SegmentTree(int sz) : n(sz), st(4*n), lazy(4*n, -1) {}
SegmentTree(const vi &initialA) : SegmentTree((int)initialA.size()) {
A = initialA;
build(1, 0, n-1);
}
void update(int i, int j, int val) { update(1, 0, n-1, i, j, val); }
int RMQ(int i, int j) { return RMQ(1, 0, n-1, i, j); }
};
int main() {
vi A;
int n, g;
int x;
int i, j;
//int v[2*DESLOQUE] = {};
map<int, int> v;
while (!cin.eof())
{
cin >> n;
if(!n)
return 0;
cin >> g;
A.clear();
/* for (int i = 0; i < 2*DESLOQUE; i++)
v[i] = 1;*/
v.clear();
for (int k = 0; k < n; ++k)
{
cin >> x;
//if(x > 0)
//v[x+ DESLOQUE]++;
v[x]++;
A.push_back(-v[x]);
}
//for (int i = 0; i < n; i++)
/*for(auto m: v)
A.push_back(-m.second);*/
for (auto m : A)
cout << m << endl;
cout << "----------------" << endl;
SegmentTree st(A);
for (int k = 0; k < g; ++k)
{
cin >> i >> j;
/*int h = st.RMQ(i-1, i-1);
st.update(i-1, i-1, h - st.RMQ(i - 2, i - 2));
for (auto m : A)
cout << h << endl;
cout << "----------------" << endl;*/
cout << i << " " << j << " -> "<< -st.RMQ(i-1,j-1) << endl;
//st.update(i-1, i-1, h);
}
}
}