Given the roots of two binary trees root and subRoot, return true if there is a subtree of root with the same structure and node values of subRoot and false otherwise.
Input: root = [3,4,5,1,2], subRoot = [4,1,2]
Output: true\
Recursive:
Check every node with subroot's root
- if there is a root and subtree equals subroot, return true
- otherwise, traverse to other nodes until all nodes are visited
Time: O(n)
Space: O(n)
Recursive
public boolean isSubtree(TreeNode root, TreeNode subRoot) {
if (root == null)
return false;
if (validate(root, subRoot))
return true;
return isSubtree(root.left, subRoot) || isSubtree(root.right, subRoot);
}
private boolean validate(TreeNode root1, TreeNode root2) {
if (root1 == null && root2 == null)
return true;
if (root1 == null || root2 == null)
return false;
if (root1.val != root2.val)
return false;
return validate(root1.left, root2.left) && validate(root1.right, root2.right);
}