algorithm_practice/two_out_of_three.py at main · cris-j-dev/algorithm_practice · GitHub

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"""
2032. Two Out of Three
Difficulty:Easy

Given three integer arrays nums1, nums2, and nums3, return a distinct array containing all the values that are present in at least two out of the three arrays.
You may return the values in any order.


Example 1:

Input: nums1 = [1,1,3,2], nums2 = [2,3], nums3 = [3]
Output: [3,2]
Explanation: The values that are present in at least two arrays are:
- 3, in all three arrays.
- 2, in nums1 and nums2.
Example 2:

Input: nums1 = [3,1], nums2 = [2,3], nums3 = [1,2]
Output: [2,3,1]
Explanation: The values that are present in at least two arrays are:
- 2, in nums2 and nums3.
- 3, in nums1 and nums2.
- 1, in nums1 and nums3.
Example 3:

Input: nums1 = [1,2,2], nums2 = [4,3,3], nums3 = [5]
Output: []
Explanation: No value is present in at least two arrays.


Constraints:

1 <= nums1.length, nums2.length, nums3.length <= 100
1 <= nums1[i], nums2[j], nums3[k] <= 100

"""


from typing import List


class Solution:
    def twoOutOfThree(
        self, nums1: List[int], nums2: List[int], nums3: List[int]
    ) -> List[int]:

        res = []
        if len(nums1) > len(nums2):
            for i in nums2:
                if i in nums1:
                    res.append(i)
        else:
            for i in nums1:
                if i in nums2:
                    res.append(i)

        if len(nums1) > len(nums3):
            for i in nums3:
                if i in nums1:
                    res.append(i)
        else:
            for i in nums1:
                if i in nums3:
                    res.append(i)

        if len(nums2) > len(nums3):
            for i in nums3:
                if i in nums2:
                    res.append(i)
        else:
            for i in nums2:
                if i in nums3:
                    res.append(i)

        return list(set(res))


if __name__ == "__main__":
    solution = Solution()
    print(solution.twoOutOfThree(nums1=[1, 1, 3, 2], nums2=[2, 3], nums3=[3]))