Given two binary strings, return their sum (also a binary string).
For example, a = "11" b = "1" Return "100"k
tag:
- string
- bit
二进制加法,注意进位
res = a^b^carry
carry = a+b+carry>1?1:0
java
public String addBinary(String a, String b) {
StringBuffer res = new StringBuffer();
int carry = 0;
int i, j;
for (i = a.length() - 1, j = b.length() - 1; i >= 0 && j >= 0; i--, j--) {
int m = a.charAt(i) - '0', n = b.charAt(j) - '0';
int r = m ^ n ^ carry;
carry = (m + n + carry) > 1 ? 1 : 0;
res.append(r);
}
if (i < 0 && j >= 0) {
while (j >= 0) {
res.append((b.charAt(j) - '0') ^ carry);
carry = (b.charAt(j) - '0') & carry;
j--;
}
if (carry == 1)
res.append(carry);
} else if (j < 0 && i >= 0) {
while (i >= 0) {
res.append((a.charAt(i) - '0') ^ carry);
carry = (a.charAt(i) - '0') & carry;
i--;
}
if (carry == 1)
res.append(carry);
} else {
if (carry > 0)
res.append(1);
}
return res.reverse().toString();
}