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genStr.py
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185 lines (166 loc) ยท 7 KB
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import asyncio
from bot import bot, HU_APP
from pyromod import listen
from asyncio.exceptions import TimeoutError
from pyrogram import filters, Client
from pyrogram.types import Message, InlineKeyboardMarkup, InlineKeyboardButton
from pyrogram.errors import (
SessionPasswordNeeded, FloodWait,
PhoneNumberInvalid, ApiIdInvalid,
PhoneCodeInvalid, PhoneCodeExpired
)
API_TEXT = """Hi, {}.
๐ I can generate pyrogram strings session for your Telegram accounts.
Send me /help for more info
โ ๏ธ Disclaimer - This bot is 100% safe. But please make sure that you properly know what a string session is & how it performs, brfore using me.๐
Bot Updates @dihanofficial
Now send your `API_ID` same as `APP_ID` to Start Generating Session.
"""
HASH_TEXT = "Now send your `API_HASH`.\n\nPress /cancel to Cancel Task."
PHONE_NUMBER_TEXT = (
"Now send your Telegram account's Phone number in International Format. \n"
"Including Country code. Example: **+9471234578**\n\n"
"Press /cancel to Cancel Task."
)
@bot.on_message(filters.private & filters.command("start"))
async def genStr(_, msg: Message):
chat = msg.chat
api = await bot.ask(
chat.id, API_TEXT.format(msg.from_user.mention)
)
if await is_cancel(msg, api.text):
return
try:
check_api = int(api.text)
except Exception:
await msg.reply("`API_ID` is Invalid.\nPress /start to Start again.")
return
api_id = api.text
hash = await bot.ask(chat.id, HASH_TEXT)
if await is_cancel(msg, hash.text):
return
if not len(hash.text) >= 30:
await msg.reply("`API_HASH` is Invalid.\nPress /start to Start again.")
return
api_hash = hash.text
while True:
number = await bot.ask(chat.id, PHONE_NUMBER_TEXT)
if not number.text:
continue
if await is_cancel(msg, number.text):
return
phone = number.text
confirm = await bot.ask(chat.id, f'`Is "{phone}" correct? (y/n):` \n\nSend: `y` (If Yes)\nSend: `n` (If No)')
if await is_cancel(msg, confirm.text):
return
if "y" in confirm.text:
break
try:
client = Client("my_account", api_id=api_id, api_hash=api_hash)
except Exception as e:
await bot.send_message(chat.id ,f"**ERROR:** `{str(e)}`\nPress /start to Start again.")
return
try:
await client.connect()
except ConnectionError:
await client.disconnect()
await client.connect()
try:
code = await client.send_code(phone)
await asyncio.sleep(1)
except FloodWait as e:
await msg.reply(f"You have Floodwait of {e.x} Seconds")
return
except ApiIdInvalid:
await msg.reply("API ID and API Hash are Invalid.\n\nPress /start to Start again.")
return
except PhoneNumberInvalid:
await msg.reply("Your Phone Number is Invalid.\n\nPress /start to Start again.")
return
try:
otp = await bot.ask(
chat.id, ("An OTP is sent to your phone number, "
"Please enter OTP in `1 2 3 4 5` format. __(Space between each numbers!)__ \n\n"
"If Bot not sending OTP then try /restart and Start Task again with /start command to Bot.\n"
"Press /cancel to Cancel."), timeout=300)
except TimeoutError:
await msg.reply("Time limit reached of 5 min.\nPress /start to Start again.")
return
if await is_cancel(msg, otp.text):
return
otp_code = otp.text
try:
await client.sign_in(phone, code.phone_code_hash, phone_code=' '.join(str(otp_code)))
except PhoneCodeInvalid:
await msg.reply("Invalid Code.\n\nPress /start to Start again.")
return
except PhoneCodeExpired:
await msg.reply("Code is Expired.\n\nPress /start to Start again.")
return
except SessionPasswordNeeded:
try:
two_step_code = await bot.ask(
chat.id,
"Your account have Two-Step Verification.\nPlease enter your Password.\n\nPress /cancel to Cancel.",
timeout=300
)
except TimeoutError:
await msg.reply("`Time limit reached of 5 min.\n\nPress /start to Start again.`")
return
if await is_cancel(msg, two_step_code.text):
return
new_code = two_step_code.text
try:
await client.check_password(new_code)
except Exception as e:
await msg.reply(f"**ERROR:** `{str(e)}`")
return
except Exception as e:
await bot.send_message(chat.id ,f"**ERROR:** `{str(e)}`")
return
try:
session_string = await client.export_session_string()
await client.send_message("me", f"#PYROGRAM #STRING_SESSION\n\n```{session_string}``` \n\nBy [@String_Session_Gen_Bot](tg://openmessage?user_id=1816235885) \nA Bot By @DihanOfficial")
await client.disconnect()
text = "โ
Congratulations! A pyrogram string session for your Telegram account was successfully created. You can find the string session in the saved messages section in your telegram account. Thank you for using me! ๐ค."
reply_markup = InlineKeyboardMarkup(
[[InlineKeyboardButton(text="๐ฅ ๐จ๐ฝ๐ฑ๐ฎ๐๐ฒ๐ ๐๐ต๐ฎ๐ป๐ป๐ฒ๐น ๐ฅ", url=f"https://t.me/dihanofficial")]]
)
await bot.send_message(chat.id, text, reply_markup=reply_markup)
except Exception as e:
await bot.send_message(chat.id ,f"**ERROR:** `{str(e)}`")
return
@bot.on_message(filters.private & filters.command("restart"))
async def restart(_, msg: Message):
await msg.reply("Restarted Bot!")
HU_APP.restart()
@bot.on_message(filters.private & filters.command("help"))
async def restart(_, msg: Message):
out = f"""
Hi, {msg.from_user.mention}. This is Pyrogram Session String Generator Bot. \
I will give you `STRING_SESSION` for your UserBot.
It needs `API_ID`, `API_HASH`, Phone Number and One Time Verification Code. \
Which will be sent to your Phone Number.
You have to put **OTP** in `1 2 3 4 5` this format. __(Space between each numbers!)__
**NOTE:** If bot not Sending OTP to your Phone Number than send /restart Command and again send /start to Start your Process.
Must Join Channel for Bot Updates !!
"""
reply_markup = InlineKeyboardMarkup(
[
[
InlineKeyboardButton('๐ฝ๐ค๐ฉ๐จ ๐๐ช๐ฅ๐ฅ๐ค๐ง๐ฉ', url='https://t.me/dihan_official'),
InlineKeyboardButton('๐ฟ๐๐ซ๐๐ก๐ค๐ฅ๐๐ง', url='https://t.me/dihanrandila')
],
[
InlineKeyboardButton('๐ฅ ๐จ๐ฝ๐ฑ๐ฎ๐๐ฒ๐ ๐๐ต๐ฎ๐ป๐ป๐ฒ๐น ๐ฅ ', url='https://t.me/dihanofficial'),
]
]
)
await msg.reply(out, reply_markup=reply_markup)
async def is_cancel(msg: Message, text: str):
if text.startswith("/cancel"):
await msg.reply("Process Cancelled.")
return True
return False
if __name__ == "__main__":
bot.run()