"%6.6d" etc do work the same as in C

[goodluck1982]

#include <stdio.h>
int main()
{
  printf("%6.6d\n",3);
  printf("%6.3d\n",3);
  printf("%-6.3d\n",3);
  printf("%+6.3d\n",3);
  printf("%-+6.3d\n",3);
  return(0);
}

The above C code gives the follwing results:

000003
   003
003   
  +003
+003

While the package "sprintf`" gives the follwing results which are different from those of C.

In[2]:= sprintf["%6.6d",3]
Out[2]=      3
In[3]:= sprintf["%6.3d",3]
Out[3]=      3
In[4]:= sprintf["%-6.3d",3]
Out[4]= 3     
In[5]:= sprintf["%+6.3d",3]                  
Out[5]=     +3
In[6]:= sprintf["%-+6.3d",3]
Out[6]= +3 

[evanberkowitz]

Hm, I didn't know you could specify integers with a . The first two cases succeed with "%06d" and " %03d" but the others do not. I will investigate.

[evanberkowitz]

@goodluck1982 Can you test the branch fix/d-zeros. If you're satisfied with the %d formatting I will merge #5 in.

I think I have covered all of the above cases, though there may still be edge cases I haven't considered.