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question_2.py
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72 lines (62 loc) · 1.49 KB
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#!/usr/bin/env python
# @Time : 2018/5/12 下午5:52
# @Author : cancan
# @File : question_2.py
# @Function : 对称二叉树
"""
Question:
给定一个二叉树,检查它是否是镜像对称的。
例如,二叉树 [1,2,2,3,4,4,3] 是对称的。
1
/ \
2 2
/ \ / \
3 4 4 3
但是下面这个 [1,2,2,null,3,null,3] 则不是镜像对称的:
1
/ \
2 2
\ \
3 3
Note:
如果你可以运用递归和迭代两种方法解决这个问题,会很加分。
"""
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def isSymmetric(self, root):
"""
:type root: TreeNode
:rtype: bool
"""
if not root:
return True
t = []
n = []
def f(node, t, n):
if node.left:
t.append(node.left)
n.append(node.left.val)
else:
n.append(None)
if node.right:
t.append(node.right)
n.append(node.right.val)
else:
n.append(None)
f(root, t, n)
while t:
l = len(n)
for _ in range(l // 2):
if n[_] != n[l - _ - 1]:
return False
p = []
n = []
for i in t:
f(i, p, n)
t = p
return True