diff --git a/Part2.md b/Part2.md
index 7781319..7280507 100644
--- a/Part2.md
+++ b/Part2.md
@@ -1,12 +1,36 @@
 ## More JavaScript questions!
 
 1. Create a function that takes 3 arguments and returns the sum of the these arguments.
+functin sum(a,b,c){
+	let sum = a+b+c; 
+	return sum;
+}
 
 2. Create a function named `colorCar` that receives a color, and prints out, _'a red car'_ for example.
+function colorCar(color){
+	console.log("a "+color+" car");
+}
+
 
 3. Create an object and a function that takes the object as a parameter and prints out all of its properties and values.
 
+var obj = { 
+param1 : "par1" ; 
+param2 : "par2" ;
+};
+
 4. Create a function named `vehicleType` that receives a color, and a code, 1 for car, 2 for motorbike. And prints _'a blue motorbike'_ for example when called as `vehicleType("blue", 2)`
+function vehicleType(color, code){
+	if (code==1){
+	console.log("a "+color+" car");
+}
+	else if (code == 2 )P{
+	console.log("a "+color+" motorbike");
+}
+	else {
+	console.log(the code is not a valid choise)
+}
+}
 
 5. Can you write the following without the `if` statement, but with just as a single line with `console.log(...);`?
 
@@ -17,12 +41,55 @@
      console.log("no");
    }
    ```
+   (3===3) ? console.log("yes") :console.log("no") ;
 
 6. Create a function called `vehicle`, like before, but takes another parameter called `age`, so that `vehicle("blue", 1, 5)` prints _'a blue used car'_
 
+function vehicle(color, code, age){
+	if ( age === 0 ){
+			if (code==1){
+				console.log("a "+color+"new car");
+				}
+			else if (code == 2 )P{
+				console.log("a "+color+"new motorbike");
+				}
+			else {
+				console.log(the code is not a valid choise)
+				}
+			}
+	else{
+			if (code==1){
+				console.log("a "+color+"Used car");
+				}
+			else if (code == 2 )P{
+				console.log("a "+color+"Used motorbike");
+				}
+			else {
+				console.log(the code is not a valid choise)
+				}
+			}
+		}
 7. Make a list of vehicles, you can add `"motorbike"`, `"caravan"`, `"bike"`, or more.
 
+ const vehicles = [];
+ 	vehicles.push("motorbike");
+ 	vehicles.push("caravan");
+ 	vehicles.push("bike");
+ 	vehicles.push("car");
+
 8. How do you get the third element from that list?
 
+console.log(vehicles[2]);
+
 9. Change the function `vehicle` to use the list of question 7. So that `vehicle("green", 3, 1)` prints "a green new bike". 
     > Hint, it should use the `code` to get the value from the list. So `vehicle("green", 2, 1)` prints "a green new caravan".
+  function vehicle(color, code, age){
+	if ( age =< 1){
+			console.log("a "+color+" new "+ vehicles[code-1]);
+		}
+	else () {
+			console.log("a "+color+ " old "+ vehicles[code-1]);
+			}
+		}
+
+			
diff --git a/ex.js b/ex.js
index d2f433d..ea61cc9 100644
--- a/ex.js
+++ b/ex.js
@@ -9,5 +9,22 @@ addFavoriteBook("The Great Gatsby");
 addFavoriteBook("Crime & Punishment");
 addFavoriteBook("Great Expectations");
 addFavoriteBook("You Don't Know JS");
+printFavoriteBooks();
+
+
+function addFavoriteBook(bookName){
+	 
+	var n = bookName.includes("Great");
+	if (!n){
+		favoriteBooks.push(bookName);
+	}
+}
+
+function printFavoriteBooks(){
+  console.log("Favorite Books :"+ favoriteBooks.length);
+  for(let elements of favoriteBooks){
+	console.log(elements);
+  }
+}
 
 // TODO: print out favorite books