-
Notifications
You must be signed in to change notification settings - Fork 1
Expand file tree
/
Copy path3.longest-substring-without-repeating-characters.python3.py
More file actions
66 lines (64 loc) · 1.31 KB
/
3.longest-substring-without-repeating-characters.python3.py
File metadata and controls
66 lines (64 loc) · 1.31 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
# coding:utf-8
# [3] Longest Substring Without Repeating Characters
#
# https://leetcode.com/problems/longest-substring-without-repeating-characters/description/
#
# algorithms
# Medium (24.99%)
# Total Accepted: 572.1K
# Total Submissions: 2.3M
# Testcase Example: '"abcabcbb"'
#
# Given a string, find the length of the longest substring without repeating
# characters.
#
#
# Example 1:
#
#
# Input: "abcabcbb"
# Output: 3
# Explanation: The answer is "abc", with the length of 3.
#
#
#
# Example 2:
#
#
# Input: "bbbbb"
# Output: 1
# Explanation: The answer is "b", with the length of 1.
#
#
#
# Example 3:
#
#
# Input: "pwwkew"
# Output: 3
# Explanation: The answer is "wke", with the length of 3.
# Note that the answer must be a substring, "pwke" is a
# subsequence and not a substring.
#
#
#
#
#
#
class Solution:
def lengthOfLongestSubstring(self, s):
"""
:type s: str
:rtype: int
"""
if s is None or len(s) < 1:
return 0
length = len(s)
res = [1 for i in range(length)]
for i in range(1, length):
search_str = s[i-res[i-1]:i][::-1]
if s[i] in search_str:
res[i] = search_str.index(s[i]) + 1
else:
res[i] = res[i-1] + 1
return max(res)