Hi!
Where is the upper-left corner?
Does four vertex of pos Rectangular have a law,?such as clockwise, counterclockwise, I think these will affect the results of the function!
function:
def bboxes_to_grasps(bboxes):
box = tf.unstack(bboxes, axis=1)
x = (box[0] + (box[4] - box[0])/2) * 0.35
y = (box[1] + (box[5] - box[1])/2) * 0.47
tan = (box[3] -box[1]) / (box[2] -box[0]) *0.47/0.35
h = tf.sqrt(tf.pow((box[2] -box[0])*0.35, 2) + tf.pow((box[3] -box[1])*0.47, 2))
w = tf.sqrt(tf.pow((box[6] -box[0])*0.35, 2) + tf.pow((box[7] -box[1])*0.47, 2))
return x, y, tan, h, w
When the grab rectangle is tilted to the left or to the right, how does the upper left corner of the rectangle behave according to the above calculation formula?
抓取矩形朝左倾斜或朝右倾斜时，如果按照上述计算公式，矩形的左上角是怎么规定的呢？
Hi!
Where is the upper-left corner?
Does four vertex of pos Rectangular have a law,?such as clockwise, counterclockwise, I think these will affect the results of the function!
function:
def bboxes_to_grasps(bboxes):
box = tf.unstack(bboxes, axis=1)
x = (box[0] + (box[4] - box[0])/2) * 0.35
y = (box[1] + (box[5] - box[1])/2) * 0.47
tan = (box[3] -box[1]) / (box[2] -box[0]) *0.47/0.35
h = tf.sqrt(tf.pow((box[2] -box[0])*0.35, 2) + tf.pow((box[3] -box[1])*0.47, 2))
w = tf.sqrt(tf.pow((box[6] -box[0])*0.35, 2) + tf.pow((box[7] -box[1])*0.47, 2))
return x, y, tan, h, w
When the grab rectangle is tilted to the left or to the right, how does the upper left corner of the rectangle behave according to the above calculation formula?
抓取矩形朝左倾斜或朝右倾斜时，如果按照上述计算公式，矩形的左上角是怎么规定的呢？