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RomantoIntegerLeetcode.cc
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108 lines (82 loc) · 2.68 KB
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class Solution {
public:
int romanToInt(string s) {
int sum=0;
for(int i=0; i<s.size(); i++){
if(s[i]=='I'){
if(i!=s.size()-1 && s[i+1]=='V'||s[i+1]=='X'||s[i+1]=='L'||s[i+1]=='C'||s[i+1]=='D'||s[i+1]=='M'){
continue;
}
else
sum+=1;
}
if(s[i]=='V'){
if(i!=s.size()-1 && s[i+1]=='X'||s[i+1]=='L'||s[i+1]=='C'||s[i+1]=='D'||s[i+1]=='M'){
continue;
}
if(i!=0 && s[i-1]=='I'){
sum+=4;
}
else{
sum+=5;
}
}
else if(s[i]=='X'){
if(i!=s.size()-1 && s[i+1]=='L'||s[i+1]=='C'||s[i+1]=='D'||s[i+1]=='M'){
continue;
}
if(i!=0 && s[i-1]=='I'){
sum+=9;
}
else{
sum+=10;
}
}
else if(s[i]=='L'){
if(i!=s.size()-1 && s[i+1]=='C'||s[i+1]=='D'||s[i+1]=='M'){
continue;
}
if(i!=0 && s[i-1]=='X'){
sum+=40;
}
else{
sum+=50;
}
}
else if(s[i]=='C'){
if(i!=s.size()-1 && s[i+1]=='D'||s[i+1]=='M'){
continue;
}
if(i!=0 && s[i-1]=='X'){
sum+=90;
}
else{
sum+=100;
}
}
else if(s[i]=='D'){
if(i!=s.size()-1 && s[i+1]=='M'){
continue;
}
if(i!=0 && s[i-1]=='C'){
sum+=400;
}
else{
sum+=500;
}
}
else if(s[i]=='M'){
if(i!=0 && s[i-1]=='C'){
sum+=900;
}
else{
sum+=1000;
}
}
}
return sum;
}
};
/* The function converts Roman numeral into integer
For example, "MCMXCIV". The function takes a string as an example and converts "MCMXCIV" to an integer equal to 1994 and return it.
*/