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DLX_extra.cpp
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144 lines (141 loc) · 3 KB
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#pragma comment(linker, "/STACK:102400000,102400000")
#include <stdio.h>
#include <iostream>
#include <algorithm>
#include <sstream>
#include <stdlib.h>
#include <string.h>
#include <limits.h>
#include <string>
#include <time.h>
#include <math.h>
#include <queue>
#include <stack>
#include <set>
#include <map>
using namespace std;
#define For(i,n) for(int i=1;i<=n;i++)
#define Fork(i,k,n) for(int i=k;i<=n;i++)
#define Rep(i,n) for(int i=0;i<n;i++)
#define ForD(i,n) for(int i=n;i;i--)
#define ForkD(i,k,n) for(int i=n;i>=k;i--)
#define RepD(i,n) for(int i=n;i>=0;i--)
#define Forp(x) for(int p=Pre[x];p;p=Next[p])
#define Forpiter(x) for(int &p=iter[x];p;p=Next[p])
#define Lson (o<<1)
#define Rson ((o<<1)+1)
#define MEM(a) memset(a,0,sizeof(a));
#define MEMI(a) memset(a,127,sizeof(a));
#define MEMi(a) memset(a,128,sizeof(a));
#define INF (0x3f3f3f3f)
#define F (100000007)
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define vi vector<int>
#define pi pair<int,int>
#define SI(a) ((a).size())
#define Pr(kcase,ans) printf("Case #%d: %lld\n",kcase,ans);
#define PRi(a,n) For(i,n-1) cout<<a[i]<<' '; cout<<a[n]<<endl;
#define PRi2D(a,n,m) For(i,n) { \
For(j,m-1) cout<<a[i][j]<<' ';\
cout<<a[i][m]<<endl; \
}
#pragma comment(linker, "/STACK:102400000,102400000")
typedef long long ll;
typedef unsigned long long ull;
ll mul(ll a,ll b){return (a*b)%F;}
ll add(ll a,ll b){return (a+b)%F;}
void upd(ll &a,ll b){a=(a%F+b%F)%F;}
int read()
{
int x=0,f=1; char ch=getchar();
while(!isdigit(ch)) {if (ch=='-') f=-1; ch=getchar();}
while(isdigit(ch)) { x=x*10+ch-'0'; ch=getchar();}
return x*f;
}
int ans=0;
struct DLX {
#define MAXNode (1000000+10)
#define maxn (1000000+10)
#define maxm (1000)
int L[MAXNode],R[MAXNode],U[MAXNode],D[MAXNode];
int sz,col[MAXNode],S[maxm],H[maxn];
bool vis[maxm];
void init(int m) {
Rep(i,m+1) {
L[i] = i-1;
R[i] = i+1;
U[i] = D[i] =i;
S[i] = 0;
}
memset(H,-1,sizeof(H));
L[0]=m; R[m] = 0;
sz=m+1;
}
#define FOR(i,A,s) for(int i=A[s];i!=s;i=A[i])
void remove(int c) {
FOR(i,D,c) {
L[R[i]] = L[i];
R[L[i]] = R[i];
}
}
void resume(int c) {
int i;
for(int i=U[c];i!=c;i=U[i]) {
L[R[i]] = R[L[i]] = i;
}
}
void link(int r,int c) {
U[sz] = c;
D[sz] = D[c];
U[D[c]] = sz;
D[c] = sz;
if (H[r]==-1) { H[r]=L[sz]=R[sz]=sz; }
else {
L[sz] =H[r];
R[sz] = R[H[r]];
L[R[H[r]]] = sz;
R[H[r]] = sz;
}
S[c]++ ; col[sz++]=c;
}
int A() {
MEM(vis)
int res=0;
FOR(i,R,0) {
if (!vis[i]) {
res++;
vis[i] = 1;
FOR(j,D,i) FOR(k,R,j) {
vis[col[k]]=1;
}
}
}
return res;
}
void dfs(int d) {
if (!R[0]) {
ans=min(ans,d);
} else if (d+A()<ans) {
int c=R[0];
FOR(i,R,0) {
if (S[i]<S[c]) c=i;
}
FOR(i,D,c) {
remove(i);
FOR(j,R,i) remove(j);
dfs(d+1);
FOR(j,L,i) resume(j);
resume(i);
}
}
}
}solver;
int main()
{
// freopen(".in","r",stdin);
// freopen(".out","w",stdout);
return 0;
}