index.js

// Iteration 1: Names and Input
/*
1.1 Create a variable hacker1 with the driver's name.*/
let hacker1 = "Darlington";
//1.2 Print "The driver's name is XXXX".
console.log ("The drivers name is ${hacker 1}");
//1.3 Create a variable hacker2 with the navigator's name.
let hacker2 = "Yena"
//1.4 Print "The navigator's name is YYYY".
console.log ("The drivers name is ${hacker 1}");

// Iteration 2: Conditionals
//2.1. Depending on which name is longer, print:
let count= hacker1.length;
console.log(count);

let count1= hacker2.length;
console.log(count1);

if(count>count1) {
    console.log(`The driver has the longest name, it has ${count}`);
} else if(count1>count) {
    console.log(`It seems that the navigator has the longest name, it has ${count1}`);
} else{
    console.log(`Wow, you both have equally long names ${count1}`);
}
//- The driver has the longest name, it has XX characters. or
//- It seems that the navigator has the longest name, it has XX characters. or
//- Wow, you both have equally long names, XX characters!.

// Iteration 3: Loops
// 3.1 Print the characters of the driver's name, separated by space, and in capital letters, i.e., "J O H N".
// console.log(hacker1);
let capitalDriver = hacker1.toUpperCase();
console.log(capitalDriver);
let splitcapDriver = capitalDriver.split("").join(" ");
console.log(splitcapDriver);


// 3.2 Print all the characters of the navigator's name in reverse order, i.e., "nhoJ".
console.log(hacker2.split('').reverse().join(''));

/*
3.3 Depending on the lexicographic order of the strings, print:

The driver's name goes first.
Yo, the navigator goes first, definitely.
What?! You both have the same name?
*/

let firstLetDri = hacker1.charAt(0);
console.log(firstLetDri);
let firstLetNav = hacker2.charAt(0);
console.log(firstLetNav);

if (firstLetDri < firstLetNav) {
    console.log(`The driver's name goes first.`);
} else if (firstLetDri > firstLetNav) {
    console.log(`Yo, the navigator goes first, definitely.`);
} else {
    console.log(`What?! You both have the same name?`);
}