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Replace p.IsPerfPair by Injective #7

@martinwintermath

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@martinwintermath

The current theory allows to work with a surjective pairing as opposed to a perfect (i.e. bijective) one. This is relevant, because with requring a perfect pairing the theory necessarily collapses back to finite dimensions. While IsPerfPair is currently available as a typeclass, Injective is not, and so it is now clear in how far (or how quickly) this can be achieved. Note that Dual.eval is an injective pairing.

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