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oppositeParity.cpp
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80 lines (60 loc) · 1.35 KB
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// https://codeforces.com/contest/1272/problem/E
#include <iostream>
#include <vector>
#include <queue>
#define INF 10000000
using namespace std;
const int N = 100001;
vector<int> adjList[N];
vector<int> fin(N, INF);
void bfs (vector<int> &firs, vector<int> &sec) {
queue<int> que;
vector<int> fin1(N, INF);
for (auto k: firs) {
que.push(k);
fin1[k] = 0;
}
while (!que.empty()) {
int curr = que.front();
que.pop();
for (auto p: adjList[curr]) {
if (fin1[p] == INF) {
fin1[p] = fin1[curr] + 1;
que.push(p);
}
}
}
for (auto l: sec) {
if (fin1[l] != INF) {
fin[l] = fin1[l];
} else {
fin[l] = -1;
}
}
}
int main ()
{
int n;
cin >>n;
vector <int> odd, even;
int arr[n];
for (int i = 0; i < n; i++) {
cin >> arr[i];
if (arr[i] % 2 == 0) {
even.push_back(i);
} else {
odd.push_back(i);
}
}
for (int i = 0; i < n; i++) {
if (i+arr[i] < n) {
adjList[i+arr[i]].push_back(i);
}
if (i-arr[i] >= 0) {
adjList[i-arr[i]].push_back(i);
}
}
bfs(even, odd);
bfs(odd, even);
for (int i = 0; i < n; i++) cout << fin[i] << "\n";
}