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FREQUENT.cpp
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142 lines (112 loc) · 2.61 KB
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#define MAX_ELEMENTS 100001
#define MAX_NODES 400004 // 2*2^(log(MAX_ELEMENTS)+1)
struct node
{
int start;
int end;
int freq;
};
struct inter_result
{
node temp;
bool valid;
} res;
int A[MAX_ELEMENTS] = {0};
int FREQ[MAX_ELEMENTS] = {0};
node NODES[MAX_NODES] = {0};
int N, Q;
int r1, r2;
// builds segmented tree
void build_tree(int node, int low, int high)
{
NODES[node].start = low;
NODES[node].end = high;
if(low > high){
return;
}
if(low == high){
NODES[node].freq = FREQ[low];
return;
}
int mid = (low + high) >> 1;
int left_node = node << 1;
int right_node = left_node + 1;
// split step.
build_tree(left_node, low, mid);
build_tree(right_node, mid + 1, high);
// merge step.
NODES[node].freq = max(NODES[left_node].freq, NODES[right_node].freq);
}
// given segment A[start...end] inclusive.
// what is the biggest "subsegment"(biggest=sum)
inter_result query(int node_, int start, int end, int low, int high)
{
inter_result result;
if(start > high || end < low){
result.valid = false;
return result;
}
if(low == high || (low >= start && high <= end)){
result.temp = NODES[node_];
result.valid = true;
return result;
}
int mid = (low + high) >> 1;
inter_result r1 = query(node_ << 1, start, end, low, mid);
inter_result r2 = query((node_ << 1) + 1, start, end, mid + 1, high);
if(!r1.valid && !r2.valid)
return r1;
if(!r1.valid) return r2;
if(!r2.valid) return r1;
// tricky business merging those babies :-)
node merged_node;
merged_node.start = low;
merged_node.end = high;
merged_node.freq = max(r1.temp.freq, r2.temp.freq);
result.temp = merged_node;
result.valid = true;
return result;
}
int main()
{
parse_data();
while(true){
N = extract_int();
if(!N) break;
Q = extract_int();
for(int j = 1; j <= N; j++)
A[j] = extract_int();
// preprocess A to frequency array B.
// should be linear hehe.
for(int j = 1; j <= N; j++){
if(j > 1 && A[j - 1] == A[j]){
FREQ[j] = FREQ[j - 1];
continue;
}
FREQ[j] = 1;
for(int i = j + 1; j <= N && A[i] == A[j]; i++, FREQ[j]++);
}
// generate segmented tree from FREQ array.
build_tree(1, 1, N);
while(Q--){
r1 = extract_int();
r2 = extract_int();
// we need to adjust r1 and r2,
// to complete query, instead of subqueries.
int n1 = 1;
int n2 = 1;
int best = 1;
for(int w = r1 + 1; w <= r2 && A[r1] == A[w]; w++) n1++;
for(int z = r2 - 1; z >= r1 && A[r2] == A[z]; z--) n2++;
best = max(n1, n2);
r1 += n1;
r2 -= n2;
if(r1 <= r2){
res = query(1, r1, r2, 1, N);
best = max(best, res.temp.freq);
}
printf("%d\n", best);
}
}
return 0;
}