codewars/arrayDiff.ts at main · rmnlpz/codewars · GitHub

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
/**
 *
 * Your goal in this kata is to implement a difference function, which subtracts one list from another and returns the result.

It should remove all values from list a, which are present in list b keeping their order.

arrayDiff([1,2],[1]) == [2]
If a value is present in b, all of its occurrences must be removed from the other:

arrayDiff([1,2,2,2,3],[2]) == [1,3] a

 * @param {*} b
 * @returns
 */

const arrayA: string[] = ['Joao', 'Maria', 'Pedro', 'Carla']
const arrayB: string[] = ['Ricardo', 'Maria', 'Pedro', 'Joao']

for (let i: number = 0; i < arrayA.length; i++) {
    for (let j: number = 0; j < arrayB.length; j++) {
        const valueA: string = arrayA[i]
        const valueB: string = arrayB[j]

        if (valueA === valueB) {
            console.log(valueA)
            break
        }
    }
    break
}


// function arrayDiff(a, b) {
//     // tem que remover os itens de A que existem em B e manter a ordem.
//     b.forEach((vb) => {
//         a.find(va => {
//             if (va === vb) {
//                 const idx = a.indexOf(vb)
//                 a[idx] = ""
//             }
//         })
//     })

//     a = a.join("").split("")

//     return a.map(x => {
//         return parseInt(x)
//     })
// }

// console.log(arrayDiff([1, 2, 3], [1]))