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LongestConsecutiveSequence.java
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38 lines (33 loc) · 967 Bytes
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/*
Given an unsorted array of integers nums, return the length of the longest consecutive elements sequence.
You must write an algorithm that runs in O(n) time.
Example 1:
Input: nums = [100,4,200,1,3,2]
Output: 4
Explanation: The longest consecutive elements sequence is [1, 2, 3, 4]. Therefore its length is 4.
Example 2:
Input: nums = [0,3,7,2,5,8,4,6,0,1]
Output: 9
Example 3:
Input: nums = [1,0,1,2]
Output: 3
*/
class Solution {
public int longestConsecutive(int[] nums) {
if(nums.length == 0) return 0;
List<Integer> list = new ArrayList<>();
Arrays.sort(nums);
int seq_len = 1;
for(int i = 0;i<nums.length-1;i++){
int diff = nums[i+1] - nums[i];
if(diff == 0) continue;
if(diff == 1) seq_len++;
else{
list.add(seq_len);
seq_len = 1;
}
}
list.add(seq_len);
return Collections.max(list);
}
}