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LazyUpdate,c
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64 lines (59 loc) · 1.26 KB
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//Solving the Lazy Updates question using difference array
#include<stdio.h>
# define mod 1000000007
long long int arr[1000005],diff[1000005], multiplier[1000005],sum[1000005];
/*long long int hash(long long int arr[100005],long long int n)
{
long long int i, multiplier[100005],sum[100005];
printf("1\n");
multiplier[0]=1;
sum[0]=arr[0]%mod;
for (i=1;i<n;++i)
{
multiplier[i]=(multiplier[i-1]*107)%mod;
sum[i]=(sum[i-1] + (multiplier[i]*arr[i])%mod)%mod;
}
return sum[n-1];
}*/
int main()
{
//long long int arr[100005],diff[100005], multiplier[100005],sum[100005];
long long int i,j,n,q,l,r,x,ans,mult;
scanf("%lld%lld",&n,&q);
for(i=0;i<n;i++)
{
scanf("%lld",&arr[i]);
}
diff[0]=arr[0];
for(i=1;i<n;i++)
{
diff[i]=arr[i]-arr[i-1];
}
for(i=0;i<q;i++)
{
scanf("%lld %lld %lld",&l,&r,&x);//
//for(j=l;j<r+1;j++)
// arr[j]+=x;
diff[l]+=x;
diff[r+1]-=x;
}
arr[0]=diff[0];
//printf("%lld ",arr[0]);
for(i=1;i<n;i++)
{
arr[i]=diff[i]+arr[i-1];
// printf("%lld ",arr[i]);
}
//ans=hash(arr,n);
multiplier[0]=1;
mult=1;
sum[0]=(arr[0]+mod)%mod;
for (i=1;i<n;++i)
{
//multiplier[i]=(multiplier[i-1]*107)%mod;
mult=(mult*107)%mod;
sum[i]=(((sum[i-1] + (mult*(arr[i]+mod)%mod)%mod)+mod)%mod);
}
printf("%lld\n",sum[n-1]);
return 0;
}