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Copy path100-same-tree.c
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100 lines (80 loc) · 2.64 KB
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#include <string>
#include <cassert>
#include <iostream>
using namespace std;
/*
Given the roots of two binary trees p and q, write a function to check if they are the same or not.
Two binary trees are considered the same if they are structurally identical, and the nodes have the same value.
Example 1:
1 1
/ \ / \
2 3 2 3
Input: p = [1,2,3], q = [1,2,3]
Output: true
Example 2:
1 1
/ \
2 2
Input: p = [1,2], q = [1,null,2]
Output: false
Example 3:
1 1
/ \ / \
2 1 1 2
Input: p = [1,2,1], q = [1,1,2]
Output: false
Constraints:
The number of nodes in both trees is in the range [0, 100].
-104 <= Node.val <= 104
*/
/* Definition for a binary tree node. */
struct TreeNode {
int val;
TreeNode *left;
TreeNode *right;
TreeNode() : val(0), left(nullptr), right(nullptr) {}
TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
};
class Solution {
public:
bool isEq(TreeNode * p, TreeNode * q) {
if(!p && !q)
return true;
else if (!p || !q)
return false;
return p->val == q->val && isEq(p->left, q->left) && isEq(p->right, q->right);
}
bool isSameTree(TreeNode* p, TreeNode* q) {
return isEq(p,q);
}
};
int main(int argc, char * argv[]) {
Solution sol;
assert(sol.isSameTree(new TreeNode(1,
new TreeNode(2),
new TreeNode(3)),
new TreeNode(1,
new TreeNode(2),
new TreeNode(3))
)
);
assert(!sol.isSameTree(new TreeNode(1,
new TreeNode(2),
nullptr),
new TreeNode(1,
nullptr,
new TreeNode(2))
)
);
assert(!sol.isSameTree(new TreeNode(1,
new TreeNode(2),
new TreeNode(1)),
new TreeNode(1,
new TreeNode(1),
new TreeNode(2))
)
);
cout << "tests is passed!" << endl;
return 0;
}