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| 1 | +/** |
| 2 | + * [2415] Reverse Odd Levels of Binary Tree |
| 3 | + * |
| 4 | + * Given the root of a perfect binary tree, reverse the node values at each odd level of the tree. |
| 5 | + * |
| 6 | + * For example, suppose the node values at level 3 are [2,1,3,4,7,11,29,18], then it should become [18,29,11,7,4,3,1,2]. |
| 7 | + * |
| 8 | + * Return the root of the reversed tree. |
| 9 | + * A binary tree is perfect if all parent nodes have two children and all leaves are on the same level. |
| 10 | + * The level of a node is the number of edges along the path between it and the root node. |
| 11 | + * |
| 12 | + * Example 1: |
| 13 | + * <img alt="" src="https://assets.leetcode.com/uploads/2022/07/28/first_case1.png" style="width: 626px; height: 191px;" /> |
| 14 | + * Input: root = [2,3,5,8,13,21,34] |
| 15 | + * Output: [2,5,3,8,13,21,34] |
| 16 | + * Explanation: |
| 17 | + * The tree has only one odd level. |
| 18 | + * The nodes at level 1 are 3, 5 respectively, which are reversed and become 5, 3. |
| 19 | + * |
| 20 | + * Example 2: |
| 21 | + * <img alt="" src="https://assets.leetcode.com/uploads/2022/07/28/second_case3.png" style="width: 591px; height: 111px;" /> |
| 22 | + * Input: root = [7,13,11] |
| 23 | + * Output: [7,11,13] |
| 24 | + * Explanation: |
| 25 | + * The nodes at level 1 are 13, 11, which are reversed and become 11, 13. |
| 26 | + * |
| 27 | + * Example 3: |
| 28 | + * |
| 29 | + * Input: root = [0,1,2,0,0,0,0,1,1,1,1,2,2,2,2] |
| 30 | + * Output: [0,2,1,0,0,0,0,2,2,2,2,1,1,1,1] |
| 31 | + * Explanation: |
| 32 | + * The odd levels have non-zero values. |
| 33 | + * The nodes at level 1 were 1, 2, and are 2, 1 after the reversal. |
| 34 | + * The nodes at level 3 were 1, 1, 1, 1, 2, 2, 2, 2, and are 2, 2, 2, 2, 1, 1, 1, 1 after the reversal. |
| 35 | + * |
| 36 | + * |
| 37 | + * Constraints: |
| 38 | + * |
| 39 | + * The number of nodes in the tree is in the range [1, 2^14]. |
| 40 | + * 0 <= Node.val <= 10^5 |
| 41 | + * root is a perfect binary tree. |
| 42 | + * |
| 43 | + */ |
| 44 | +pub struct Solution {} |
| 45 | +use crate::util::tree::{TreeNode, to_tree}; |
| 46 | + |
| 47 | +// problem: https://leetcode.com/problems/reverse-odd-levels-of-binary-tree/ |
| 48 | +// discuss: https://leetcode.com/problems/reverse-odd-levels-of-binary-tree/discuss/?currentPage=1&orderBy=most_votes&query= |
| 49 | + |
| 50 | +// submission codes start here |
| 51 | + |
| 52 | +// Definition for a binary tree node. |
| 53 | +// #[derive(Debug, PartialEq, Eq)] |
| 54 | +// pub struct TreeNode { |
| 55 | +// pub val: i32, |
| 56 | +// pub left: Option<Rc<RefCell<TreeNode>>>, |
| 57 | +// pub right: Option<Rc<RefCell<TreeNode>>>, |
| 58 | +// } |
| 59 | +// |
| 60 | +// impl TreeNode { |
| 61 | +// #[inline] |
| 62 | +// pub fn new(val: i32) -> Self { |
| 63 | +// TreeNode { |
| 64 | +// val, |
| 65 | +// left: None, |
| 66 | +// right: None |
| 67 | +// } |
| 68 | +// } |
| 69 | +// } |
| 70 | +use std::cell::RefCell; |
| 71 | +use std::rc::Rc; |
| 72 | +impl Solution { |
| 73 | + pub fn reverse_odd_levels( |
| 74 | + root: Option<Rc<RefCell<TreeNode>>>, |
| 75 | + ) -> Option<Rc<RefCell<TreeNode>>> { |
| 76 | + Self::dfs_helper(root.clone(), None, 0); |
| 77 | + |
| 78 | + root |
| 79 | + } |
| 80 | + |
| 81 | + fn dfs_helper( |
| 82 | + left: Option<Rc<RefCell<TreeNode>>>, |
| 83 | + right: Option<Rc<RefCell<TreeNode>>>, |
| 84 | + level: i32, |
| 85 | + ) { |
| 86 | + let rev = level & 0x01 == 1; |
| 87 | + match (left.clone(), right.clone()) { |
| 88 | + (Some(l_node), None) => { |
| 89 | + Self::dfs_helper( |
| 90 | + l_node.borrow().left.clone(), |
| 91 | + l_node.borrow().right.clone(), |
| 92 | + level + 1, |
| 93 | + ); |
| 94 | + } |
| 95 | + (Some(l_node), Some(r_node)) => { |
| 96 | + if rev { |
| 97 | + let lval = l_node.borrow().val; |
| 98 | + let rval = r_node.borrow().val; |
| 99 | + l_node.borrow_mut().val = rval; |
| 100 | + r_node.borrow_mut().val = lval; |
| 101 | + } |
| 102 | + |
| 103 | + Self::dfs_helper( |
| 104 | + l_node.borrow().left.clone(), |
| 105 | + r_node.borrow().right.clone(), |
| 106 | + level + 1, |
| 107 | + ); |
| 108 | + Self::dfs_helper( |
| 109 | + l_node.borrow().right.clone(), |
| 110 | + r_node.borrow().left.clone(), |
| 111 | + level + 1, |
| 112 | + ); |
| 113 | + } |
| 114 | + (None, Some(r_node)) => { |
| 115 | + Self::dfs_helper( |
| 116 | + r_node.borrow().left.clone(), |
| 117 | + r_node.borrow().right.clone(), |
| 118 | + level + 1, |
| 119 | + ); |
| 120 | + } |
| 121 | + _ => {} |
| 122 | + } |
| 123 | + } |
| 124 | +} |
| 125 | + |
| 126 | +// submission codes end |
| 127 | + |
| 128 | +#[cfg(test)] |
| 129 | +mod tests { |
| 130 | + use super::*; |
| 131 | + |
| 132 | + #[test] |
| 133 | + fn test_2415_example_1() { |
| 134 | + let root = tree![2, 3, 5, 8, 13, 21, 34]; |
| 135 | + |
| 136 | + let result = tree![2, 5, 3, 8, 13, 21, 34]; |
| 137 | + |
| 138 | + assert_eq!(Solution::reverse_odd_levels(root), result); |
| 139 | + } |
| 140 | + |
| 141 | + #[test] |
| 142 | + fn test_2415_example_2() { |
| 143 | + let root = tree![7, 13, 11]; |
| 144 | + |
| 145 | + let result = tree![7, 11, 13]; |
| 146 | + |
| 147 | + assert_eq!(Solution::reverse_odd_levels(root), result); |
| 148 | + } |
| 149 | + |
| 150 | + #[test] |
| 151 | + fn test_2415_example_3() { |
| 152 | + let root = tree![0, 1, 2, 0, 0, 0, 0, 1, 1, 1, 1, 2, 2, 2, 2]; |
| 153 | + |
| 154 | + let result = tree![0, 2, 1, 0, 0, 0, 0, 2, 2, 2, 2, 1, 1, 1, 1]; |
| 155 | + |
| 156 | + assert_eq!(Solution::reverse_odd_levels(root), result); |
| 157 | + } |
| 158 | +} |
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