which *> was inspired by?
#4278
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LukaJCB
KisaragiEffective
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Hello, I'm wondering where |
Answered by
LukaJCB
Aug 9, 2022
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It's based on the same operator defined in Haskell's |
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danicheg
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It's based on the same operator defined in Haskell's
Applicativetypeclass: https://hackage.haskell.org/package/base-4.17.0.0/docs/Control-Applicative.html#v:-42--62-