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PathSum.py
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22 lines (21 loc) · 750 Bytes
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# Definition for a binary tree node
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
# @param root, a tree node
# @param sum, an integer
# @return a boolean
def hasPathSum(self, root, sum):
if root and root.left and root.right:
return self.hasPathSum(root.left, sum - root.val) or self.hasPathSum(root.right, sum - root.val)
elif root and root.left:
return self.hasPathSum(root.left, sum - root.val)
elif root and root.right:
return self.hasPathSum(root.right, sum - root.val)
else:
if root and root.val == sum:
return True
return False