diff --git a/02_activities/assignments/Cohort_8/Entity Relationship Diagram.pdf b/02_activities/assignments/Cohort_8/Entity Relationship Diagram.pdf
new file mode 100644
index 000000000..96c3c8ada
Binary files /dev/null and b/02_activities/assignments/Cohort_8/Entity Relationship Diagram.pdf differ
diff --git a/02_activities/assignments/Cohort_8/assignment1.sql b/02_activities/assignments/Cohort_8/assignment1.sql
index c992e3205..d51a6c0db 100644
--- a/02_activities/assignments/Cohort_8/assignment1.sql
+++ b/02_activities/assignments/Cohort_8/assignment1.sql
@@ -4,17 +4,21 @@
 
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
-
-
+SELECT *
+FROM customer;
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
-
-
+SELECT *
+FROM customer
+ORDER by customer_last_name, customer_first_name
+LIMIT 10;
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
-
+SELECT *
+FROM customer_purchases
+WHERE product_id IN (4, 9);
 
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
@@ -23,10 +27,16 @@ filtered by customer IDs between 8 and 10 (inclusive) using either:
 	2.  one condition using BETWEEN
 */
 -- option 1
-
+SELECT * ,
+	quantity * cost_to_customer_per_qty as price
+FROM customer_purchases
+WHERE customer_id >7 AND customer_id <10;
 
 -- option 2
-
+SELECT * ,
+	quantity * cost_to_customer_per_qty as price
+FROM customer_purchases
+WHERE customer_id BETWEEN 8 and 10;
 
 
 --CASE
@@ -35,27 +45,58 @@ Using the product table, write a query that outputs the product_id and product_n
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
 
+SELECT
+product_id, 
+product_name,
+CASE
+    WHEN product_qty_type = 'unit' THEN 'unit'
+    ELSE 'bulk'
+	END AS prod_qty_type_condensed
+FROM product;
 
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
-
+SELECT
+product_id, 
+product_name,
+CASE
+    WHEN product_name LIKE '%pepper%' THEN '1'
+    ELSE '0'
+	END AS pepper_flag
+FROM product;
 
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
-
-
-
+SELECT
+v.vendor_name,
+v.vendor_id,
+v.vendor_type,
+vba.booth_number,
+vba.market_date
+
+FROM vendor as v
+inner JOIN vendor_booth_assignments as vba
+WHERE v.vendor_id = vba.vendor_id
+ORDER by vendor_name, market_date;
 
 /* SECTION 3 */
 
 -- AGGREGATE
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
-
+SELECT
+v.vendor_name,
+v.vendor_id,
+COUNT(*) AS booth_assignments
+FROM vendor v
+JOIN vendor_booth_assignments vba
+  ON v.vendor_id = vba.vendor_id
+GROUP BY v.vendor_id, v.vendor_name
+ORDER BY booth_assignments DESC, v.vendor_name;
 
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
@@ -64,7 +105,17 @@ of customers for them to give stickers to, sorted by last name, then first name.
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
 
-
+SELECT
+c.customer_id,
+c.customer_last_name,
+c.customer_first_name,
+round (SUM(cp.quantity * cp.cost_to_customer_per_qty),2) AS total_spent
+FROM customer c 
+JOIN customer_purchases cp
+	on c.customer_id = cp.customer_id
+GROUP by c.customer_id, c.customer_last_name, c.customer_first_name
+HAVING sum(cp.quantity * cp.cost_to_customer_per_qty) > 2000
+ORDER by c.customer_last_name, c.customer_first_name;
 
 --Temp Table
 /* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: 
@@ -77,8 +128,19 @@ When inserting the new vendor, you need to appropriately align the columns to be
 -> To insert the new row use VALUES, specifying the value you want for each column:
 VALUES(col1,col2,col3,col4,col5) 
 */
-
-
+DROP TABLE IF EXISTS temp.new_vendor;
+CREATE TABLE temp.new_vendor AS
+SELECT vendor_id,
+       vendor_name,
+       vendor_type,
+       vendor_owner_first_name,
+       vendor_owner_last_name
+FROM vendor;
+
+INSERT INTO temp.new_vendor
+  (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
+VALUES
+  (10, 'Thomass Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal')
 
 -- Date
 /*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
@@ -93,4 +155,3 @@ Remember that money spent is quantity*cost_to_customer_per_qty.
 
 HINTS: you will need to AGGREGATE, GROUP BY, and filter...
 but remember, STRFTIME returns a STRING for your WHERE statement!! */
-