Array Loop List Map

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title: Array-Loop-List-Map permalink: GroovyNotes/Array-Loop-List-Map category: GroovyNotes parent: GroovyNotes layout: default has_children: false share: true shortRepo:

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Table of contents

{: .text-delta } 1. TOC {:toc}

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Array

Int[] arr = [1, 2, 3]

To loop

20.times { print }

1.upto(10) { num -> println }

10.downto(1)

0.step(1, 0.1)

List

Def list = [1, 2, 3, ..]

List.size

List <<

List.push**_ adds i

List.putat(0,)

List[1] = 77

List.Removeat

//removes at index 1

Remove(1)

//removes element with that value

Remove(“ c ”)

List.removeAll { it == 2 }

Better remove all removes list from list also

list.removeall(list2)

userAuthList -= grantedAuthListToRemove

List.minus

List – [object]

List.pop //remove last item

List.Getat(0..3)   //  range

List.clear

For(x in list) { print x }

The result is a flattened single List of objects: from [[1,2], 1, 2] to [1,2,1,2]

List.flatten
//for
//lists in lists

List.unique

List.each { print it }

creates list of tuples element, index] , [element, index

arr.withIndex().findIndexOf { element, index -> isEven(element) }

map

arr.indexed().findIndexOf { e -> fn(e.value, e.key) }

List.find { it == 2 }

List.findAll { it >= 2 }

Finding and getting a specific value

user.dam = damList.find { it.userId == user.id }.damName

join() iterates over each element, concatenating every element with the character given as the input parameter.

List.join(‘ ‘)

Using negative numbers starts on the right, this will get the last number

list[-1]

runs list in reverse closuer

list.reverseEach {}

list.eachWithIndex {}

returns list in reverse in place

list.reverse(true)

The collect() method, like each(), invokes the closure for each element of the collection. However, it collects the return value from the closure into a collection and finally returns that resulting collection

list.collect { it * 2 }

Mylist.sum()

Will drop first 3 elements, does not change array

List.drop(3)

Returns boolean Modifies this collection so that it retains only its elements that are matched according to the specified closure condition. In other words, removes from this collection all of its elements that don't match.

List.retainAll {}

Opposite of retain

List.removeAll {}

Mylist.inject { variable, element -> variable + element.size() }

// With the inject method we 'inject' the

// first value of the result, and then for

// each item the result is increased and

// returned for the next iteration.

def sum = (1..4).inject(0) { result, i -> result + i }

assert 10 == sum

Merges two lists Modifies in place

Mylist.addall(secondlist)

Gets similar elements

Mylist.intersect

Tests if there are common elements, if not returns true

Mylist.disjoint

Checks if any element meets condition return Boolean

list.any()

checks if every element meets condition returns Boolean fyi - groovy every closure will return true if empty list, even though condition is not met

list.every()

use condition and mutate return

println Employee.list().findResults { it.salary > 25000 ? (firstName + ' ' + lastName) : null }

** transform items from a collection into a collection. The resulting collection is then flattened into a single collection**

list.collectMany { [it, it.toUpperCase()] }

is a method on any Iterable to split or partition its elements into a sub-list of a certain size

List.collate(size)

The result is a map where the key is the grouping condition and the value contains the elements of the Collection type belonging to the key

list.groupBy {}

Groovy collectEntries iterates over a collection and return a Map based on the manipulations Groovy collectEntries iterates over a collection and return a Map based on the manipulations

List.collectEntries {}

example using groupBy and collectEntries

    savedUserResponses.groupBy { it.fitGuideType }.collectEntries {
    [it.key, it.value.collectEntries { [('Q' + it.questionNumber.toString()): it.rating] }]
}

-list of strings to long

sharedGroupIds?.collect { Long.valueOf(it) }

paginate or split list substring(beginning index, ending index)

Paginate

response.sort { it.groupName }.subList(Math.min(5 as Integer, 21), Math.min((5 as Integer) + (10 as Integer), 21))

Maps

Def map = [key: value]

Map.put(‘ key ’, ‘ value ’)

Map[‘ yourKey ’] = yourValue

Map.’ yourKey ’ = yourValue

Map << [yourKey: yourValue]

Create or add to map To use a variable as key, put variable in ()

Map.values print only values

Map.keySet()

Get list
of keys

Map.’ key ’

Will get value

Map.find { key, value -> value.size() > 3 }

find and return value

mymap.find { it.key == "likes" }?.value

Map.each { key, value -> println “ $key and $value ” }

Checks if any element meets condition return Boolean Map.any()

Map.every()
//checks
//if
//every element meets condition returns Boolean

Map.remove(‘ key ’) //removes object in place

Map.minus([key: value]) //removes map values

Returns the value to which the specified key is mapped, or defaultValue if this map contains no mapping for the key.

Map.getOrDefault()

params is a Map, so you can use params.containsKey(keyYourWanting):

map.subMap()

change a key in a map

 List<String> keys = new ArrayList<>(runMap.keySet(
))

 keys.each { key ->
    if (testMap.get(key)) {
        runMap.put("${testMap[key]}", runMap.remove(key))
    }
}

HQL create map

 static List getGroupsByUser(Long userId, Long clientSetupId, def offset = 0, def max = 0, String orderBy = 'ug.name', String orderByDirection =
        'asc') {
    def query = """ 
      select new Map(ug.id as id, ug.name as name, ug.interviewModelId as interviewModelId,
      im.name as assessmentName,  im.sourceId as sourceId, im.source as source, im.subType as subType,
      ug.visibility as visibility, ugs.id is not null as shared , ug.lastUpdated as lastUpdated , COUNT(ugao.id) as assessmentCount) 
      from UserGroup ug  
      LEFT JOIN UserGroupAssessmentOrder ugao ON ug.id= ugao.userGroupId 
      LEFT JOIN ug.userGroupShare ugs ON ug.id = ugs.userGroupId and ugs.revoked = false
      LEFT JOIN InterviewModel im ON im.id = ug.interviewModelId
      where ug.userId = :userId and ug.type = :type and ug.clientSetupId = :clientSetupId
      GROUP BY ug.id
     order by @orderBy@ @orderByDirection@"""

    def modifiedQuery = query.replaceAll('@orderBy@', orderBy).replaceAll('@orderByDirection@', orderByDirection)

    findAll(modifiedQuery, [userId: userId, type: UserGroupType.RESULTGROUP, clientSetupId:
            clientSetupId], [offset: offset, max: max, cache: true])
}

Map with closure example

shareResultsList = results.findAll { result ->
    def catalogDetailProperties = [enableTalentCard         : result?.enableTalentCard, externalPredictionReceive: result?.externalPredictionReceive,
                                   internalPredictionReceive: result?.internalPredictionReceive, profileReceive: result?.profileReceive]

    def isValid = isValidTalentCardRecipient(catalogDetailProperties, result?.assessmentPurpose)
    isValid == true
}.collect { result -> [resultId: result?.resultId, firstName: result?.firstName, lastName: result?.lastName, email: result?.email] }

Get MAP index using keys hashmaps do not have an order

Object[] keys = map.keySet().toArray()

map.get(keys[i])

Multiput

  LinkedHashMap.metaClass.multiPut << { key, value ->
    delegate[key] = delegate[key] ?: []; delegate[key] += value
}


def myMap = [:]

myMap.multiPut("a", "1")
myMap.multiPut("a", "2")
myMap.multiPut("a", "3")

myMap.each { key, list ->
    println "${key} -> $value.list(", ")
}