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6 changes: 3 additions & 3 deletions project.ptx
Original file line number Diff line number Diff line change
Expand Up @@ -4,13 +4,13 @@
<target name="html" format="html" source="apex.ptx" publication="publication-video.ptx">
<stringparams key="html.annotation" value="hypothesis"/>
</target>
<target name="html-novideo" format="html" source="apex.ptx" publication="publication-novid.ptx">
<target name="html-novideo" format="html" source="apex.ptx" publication="publication-web-novid.ptx">
<stringparams key="html.annotation" value="hypothesis"/>
</target>
<target name="html-standard" format="html" source="apex-UL-standard.ptx" publication="publication-standard.ptx">
<target name="html-standard" format="html" source="apex-UL-standard.ptx" publication="publication-standard-web.ptx">
<stringparams key="html.annotation" value="hypothesis"/>
</target>
<target name="html-accelerated" format="html" source="apex-UL-accelerated.ptx" publication="publication-accelerated.ptx">
<target name="html-accelerated" format="html" source="apex-UL-accelerated.ptx" publication="publication-accelerated-web.ptx">
<stringparams key="html.annotation" value="hypothesis"/>
</target>
<target name="runestone" format="html" source="apex.ptx" publication="publication-runestone.ptx" output-dir="../published/APEX">
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15 changes: 6 additions & 9 deletions ptx/sec_ABC.ptx
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Expand Up @@ -245,7 +245,7 @@
as shown in <xref ref="fig_abc1"/>.
</p>

<figure xml:id="fig_abc1" vshift="3">
<figure xml:id="fig_abc1" vshift="2">
<caption>Graphing an enclosed region in <xref ref="ex_abc1"/></caption>
<!-- START figures/fig_abc1.tex -->
<image width="47%">
Expand Down Expand Up @@ -403,7 +403,7 @@
<m>y=-(x-1)^2+3</m> and <m>y=2</m>,
as shown in <xref ref="fig_abc3"/>.
</p>
<figure xml:id="fig_abc3" vshift="0">
<figure xml:id="fig_abc3" vshift="-1">
<caption>Graphing a region for <xref ref="ex_abc3"/></caption>
<!-- START figures/fig_abc3.tex -->
<image width="47%">
Expand Down Expand Up @@ -939,8 +939,7 @@

<introduction>
<p>
In the following exercises,
find the area of the shaded region in the given graph.
Find the area of the shaded region in the given graph.
</p>
</introduction>

Expand Down Expand Up @@ -1454,8 +1453,7 @@

<introduction>
<p>
In the following exercises,
find the total area enclosed by the functions <m>f</m> and <m>g</m>.
Find the total area enclosed by the functions <m>f</m> and <m>g</m>.
</p>
</introduction>
<!-- Exercise 11 -->
Expand Down Expand Up @@ -1685,7 +1683,7 @@
<exercisegroup cols="2" xml:id="exset-area-between-two-ways">
<introduction>
<p>
In the following exercises, find the area of the enclosed region in two ways:
Find the area of the enclosed region in two ways:
</p>

<p>
Expand Down Expand Up @@ -2107,8 +2105,7 @@

<introduction>
<p>
In the following exercises,
find the area of the triangle formed by the given three points.
Find the area of the triangle formed by the given three points.
</p>
</introduction>
<!-- Exercise 23 -->
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12 changes: 7 additions & 5 deletions ptx/sec_FTC.ptx
Original file line number Diff line number Diff line change
Expand Up @@ -1039,6 +1039,8 @@
Let's practice this once more.
</p>

<enlarge-page skipsize="2"/>

<example xml:id="ex_ftc12">
<title>The FTC, Part 1, and the Chain Rule</title>
<statement>
Expand Down Expand Up @@ -1229,7 +1231,7 @@
as done in <xref ref="fig_ftc6"/>.
</p>

<figure xml:id="fig_ftc6" vshift="2">
<figure xml:id="fig_ftc6" vshift="0">
<caption>Sketching the region enclosed by <m>y=x^2+x-5</m> and <m>y=3x-2</m> in <xref ref="ex_ftc6"/></caption>
<image width="47%">
<shortdescription>
Expand Down Expand Up @@ -1294,7 +1296,7 @@
</md>
</p>
</solution>
<solution component="video" vshift="2">
<solution component="video" vshift="5">
<title>Video solution</title>
<video width="98%" youtube="su2CXdpYPdo" label="vid_int_FTC_ex_4" component="video"/>
</solution>
Expand All @@ -1306,7 +1308,7 @@
The video example in <xref ref="vid_int_FTC_ex_5"/> illustrates this phenomenon.
</p>

<figure xml:id="vid_int_FTC_ex_5" component="video" vshift="-2">
<figure xml:id="vid_int_FTC_ex_5" component="video" vshift="2">
<caption>Finding the area between curves that intersect multiple times</caption>
<video youtube="Bgji1b7Wdr4" label="vid_int_FTC_ex_5"/>
</figure>
Expand Down Expand Up @@ -1527,7 +1529,7 @@
</statement>
</theorem>

<figure xml:id="vid_int_FTC_MVT_int" component="video" vshift="0">
<figure xml:id="vid_int_FTC_MVT_int" component="video" vshift="5">
<caption>Video presentation of <xref ref="thm_mvt2"/></caption>
<video youtube="KD90CwK0PJk" label="vid_int_FTC_MVT_int"/>
</figure>
Expand All @@ -1542,7 +1544,7 @@
we leave it to the reader to see how.
</p>

<aside vshift="0">
<aside vshift="1">
<p>
<xref ref="thm_mvt2"/>
simply says that there is a rectangle with height <m>f(c)</m> and width <m>b-a</m>,
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37 changes: 17 additions & 20 deletions ptx/sec_Graphical_Numerical.ptx
Original file line number Diff line number Diff line change
Expand Up @@ -1383,6 +1383,7 @@
<p>
Let's practice Euler's Method using a few concrete examples.
</p>

<example xml:id="ex_euler1">
<title>Using Euler's Method 1</title>
<statement>
Expand All @@ -1407,13 +1408,9 @@
</md>.
</p>
<p>
Using Euler's method, we find the approximate <m>y(2) \approx -0.75</m>.
</p>
<p>
To help visualize the Euler's method approximation, these three points
(connected by line segments)
are plotted along with the analytical solution to the initial value problem in <xref ref="fig_20_01_euler1"/>.
Using Euler's method, we find the approximation <m>y(2) \approx -0.75</m>.
</p>

<figure xml:id="fig_20_01_euler1" vshift="2">
<caption>Euler's Method approximation to <m>\yp = x + y</m> with <m>y(1) = -1</m> from <xref ref="ex_euler1"/>,
along with the analytical solution to the initial value problem</caption>
Expand Down Expand Up @@ -1452,6 +1449,12 @@
</latex-image>
</image>
</figure>

<p>
To help visualize the Euler's method approximation, these three points
(connected by line segments)
are plotted along with the analytical solution to the initial value problem in <xref ref="fig_20_01_euler1"/>.
</p>
</solution>
</example>

Expand Down Expand Up @@ -1498,7 +1501,7 @@
along with the points from <xref ref="ex_euler1"/> and the analytic solution,
are plotted in <xref ref="fig_20_01_euler2"/>.
</p>
<figure xml:id="fig_20_01_euler2" vshift="0">
<figure xml:id="fig_20_01_euler2" vshift="3">
<caption>Euler's Method approximations to <m>\yp = x + y</m> with <m>y(1) = -1</m> from <xref ref="ex_euler1" text="global">Examples</xref>
and <xref ref="ex_euler2" text="global"/>, along with the analytical solution</caption>
<image width="47%">
Expand Down Expand Up @@ -1642,7 +1645,7 @@
are plotted in <xref ref="fig_20_01_euler3"/>.
Notice how well they seem to match the true solution.
</p>
<figure xml:id="fig_20_01_euler3" vshift="2">
<figure xml:id="fig_20_01_euler3" vshift="3">
<caption>Euler's Method approximation to <m>\yp = y(1-y)</m> with <m>y(0) = 0.25</m> from <xref ref="ex_euler3"/>,
along with the analytical solution</caption>
<image width="47%">
Expand Down Expand Up @@ -1803,8 +1806,7 @@
<exercisegroup cols="2" xml:id="exset-graphical-numerical-verify-sol">
<introduction>
<p>
In the following exercises,
verify that the given function is a solution to the differential equation or initial value problem.
Verify that the given function is a solution to the differential equation or initial value problem.
</p>
</introduction>

Expand Down Expand Up @@ -1879,8 +1881,7 @@
<exercisegroup cols="2" xml:id="exset-graphical-numerical-verify-particular">
<introduction>
<p>
In the following exercises,
verify that the given function is a solution to the differential equation and find the <m>C</m>
Verify that the given function is a solution to the differential equation and find the <m>C</m>
value required to make the function satisfy the initial condition.
</p>
</introduction>
Expand Down Expand Up @@ -1931,8 +1932,7 @@
<exercisegroup cols="2" xml:id="exset-graphical-numerical-sketch-slope">
<introduction>
<p>
In the following exercises,
sketch a slope field for the given differential equation.
Sketch a slope field for the given differential equation.
Let <m>x</m> and <m>y</m> range between <m>-2</m> and <m>2</m>.
</p>
</introduction>
Expand Down Expand Up @@ -2298,8 +2298,7 @@
<exercisegroup cols="2" xml:id="exset-graphical-numerical-sketch-sol">
<introduction>
<p>
In the following exercises,
sketch the slope field for the differential equation,
Sketch the slope field for the differential equation,
and use it to draw a sketch of the solution to the initial value problem.
</p>
</introduction>
Expand Down Expand Up @@ -2510,8 +2509,7 @@
<exercisegroup cols="2" xml:id="exset-graphical-numerical-euler">
<introduction>
<p>
In the following exercises,
use Euler's Method to make a table of values that approximates the solution to the initial value problem on the given interval.
Use Euler's Method to make a table of values that approximates the solution to the initial value problem on the given interval.
Use the specified <m>h</m> or <m>N</m> value.
</p>
</introduction>
Expand Down Expand Up @@ -2638,8 +2636,7 @@
<exercisegroup>
<introduction>
<p>
In the following exercises,
use the provided solution <m>y(x)</m> and Euler's Method with the <m>h=0.2</m> and <m>h=0.1</m> to complete the following table.
Use the provided solution <m>y(x)</m> and Euler's Method with the <m>h=0.2</m> and <m>h=0.1</m> to complete the following table.
</p>
<tabular>
<col right="minor"/>
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11 changes: 5 additions & 6 deletions ptx/sec_Linear.ptx
Original file line number Diff line number Diff line change
Expand Up @@ -280,7 +280,7 @@
<p>
Integrating,
<md>
\ln \mu = \int p(x)\,dx
\ln(\mu) = \int p(x)\,dx
</md>,
or
<md>
Expand Down Expand Up @@ -776,7 +776,7 @@
<exercisegroup cols="2" xml:id="exset-ode-linear-general-sol">
<introduction>
<p>
In the following exercises, Find the general solution to the first order linear differential equation.
Find the general solution to the first order linear differential equation.
</p>
</introduction>
<exercise label="ex-ode-linear-general-sol-1">
Expand Down Expand Up @@ -879,7 +879,7 @@
<exercisegroup cols="2" xml:id="exset-ode-linear-particular-sol">
<introduction>
<p>
In the following exercises, Find the particular solution to the initial value problem.
Find the particular solution to the initial value problem.
</p>
</introduction>
<exercise label="ex-ode-linear-particular-sol-1">
Expand Down Expand Up @@ -982,8 +982,7 @@
<exercisegroup cols="2" xml:id="exset-ode-linear-classify">
<introduction>
<p>
In the following exercises,
classify the differential equation as separable,
Classify the differential equation as separable,
first order linear, or both,
and solve the initial value problem using an appropriate method.
</p>
Expand Down Expand Up @@ -1040,7 +1039,7 @@
<exercisegroup cols="2" xml:id="exset-ode-linear-slope">
<introduction>
<p>
In the following exercises, draw a slope field for the differential equation.
Draw a slope field for the differential equation.
Use the slope field to predict the behavior of the solution to the initial value problem for large <m>x</m> values.
Solve the initial value problem,
and verify your prediction.
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3 changes: 1 addition & 2 deletions ptx/sec_Modeling.ptx
Original file line number Diff line number Diff line change
Expand Up @@ -793,8 +793,7 @@
<exercisegroup cols="2" xml:id="exset-ode-modelling">
<introduction>
<p>
In the following exercises,
use the tools in the section to answer the questions presented.
Use the tools in the section to answer the questions presented.
</p>
</introduction>
<exercise label="ex-ode-modelling-proportional">
Expand Down
13 changes: 5 additions & 8 deletions ptx/sec_Separable.ptx
Original file line number Diff line number Diff line change
Expand Up @@ -501,13 +501,13 @@
The general solution the logistic differential equation is the set containing <m>\displaystyle y = \frac{M}{1 + be^{-kt}}</m> and <m>y=0</m>.
</p>
</solution>
<solution component="video" vshift="4">
<solution component="video" vshift="5">
<title>Video solution</title>
<video width="98%" youtube="nLItalqug6A" label="vid-diffeq-separable-example-logistic" component="video"/>
</solution>
</example>

<aside vshift="-1">
<aside vshift="1">
<p>
Solving for <m>y</m> initially yields the explicit solution <m>\displaystyle y = \frac{AMe^{kt}}{1+Ae^{kt}}</m>.
Dividing numerator and denominator by <m>Ae^{kt}</m> and defining <m>b = 1/A</m>
Expand All @@ -522,8 +522,7 @@
<exercisegroup cols="2" xml:id="exset-ode-separable-determine">
<introduction>
<p>
In the following exercises,
decide whether the differential equation is separable or not separable.
Decide whether the differential equation is separable or not separable.
If the equation is separable, write it in separated form.
</p>
</introduction>
Expand Down Expand Up @@ -581,8 +580,7 @@
<exercisegroup cols="2" xml:id="exset-ode-separable-general-sol">
<introduction>
<p>
In the following exercises,
find the general solution to the separable differential equation.
Find the general solution to the separable differential equation.
Be sure to check for missing constant solutions.
</p>
</introduction>
Expand Down Expand Up @@ -686,8 +684,7 @@
<exercisegroup cols="2" xml:id="exset-ode-separable-particular-sol">
<introduction>
<p>
In the following exercises,
find the particular solution to the separable initial value problem.
Find the particular solution to the separable initial value problem.
</p>
</introduction>
<exercise label="ex-ode-separable-particular-sol-1">
Expand Down
10 changes: 4 additions & 6 deletions ptx/sec_alt_series.ptx
Original file line number Diff line number Diff line change
Expand Up @@ -146,7 +146,7 @@
the sum of the series.
</p>

<figure xml:id="fig_alt_series_converge_a" vshift="0">
<figure xml:id="fig_alt_series_converge_a" vshift="-1">
<caption>Illustrating convergence with the Alternating Series Test</caption>
<!-- START figures/fig_alt_series_converge.tex -->
<image width="47%">
Expand Down Expand Up @@ -994,8 +994,7 @@

<introduction>
<p>
In the following exercises,
an alternating series <m>\ds \sum_{n=i}^\infty a_n</m> is given.
An alternating series <m>\ds \sum_{n=i}^\infty a_n</m> is given.
</p>

<p>
Expand Down Expand Up @@ -1588,7 +1587,7 @@
<introduction>
<p>
Let <m>S_n</m> be the <m>n^{ th }</m> partial sum of a series.
In the following exercises a convergent alternating series is given and a value of <m>n</m>.
A convergent alternating series is given and a value of <m>n</m>.
Compute <m>S_n</m> and <m>S_{n+1}</m> and use these values to find bounds on the sum of the series.
</p>
</introduction>
Expand Down Expand Up @@ -1682,8 +1681,7 @@

<introduction>
<p>
In the following exercises,
a convergent alternating series is given along with its sum and a value of <m>\varepsilon</m>.
A convergent alternating series is given along with its sum and a value of <m>\varepsilon</m>.
Use <xref ref="thm_alt_series_approx"/>
to find <m>n</m> such that the
<m>n</m>th partial sum of the series is within
Expand Down
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