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Though I did not specify it, it would have been nice if this solution included a class that had methods that performed each of the tasks asked. |
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| 1.upto(initial_num) do |n| | ||
| waiting.enqueue(rand(100..999)) | ||
| end |
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Yay! Random people! But what if we get the same ID number twice?
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Looks good. Just posed some questions on OOP and expandability ability. |
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I based my assignment off of the notes in the powerpoint slide. I added the directions I followed to a read-me file for reference.