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refactor: S10.13 Security policies + CRC + Sync primitives conformance #384
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DavidCozens
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May 17, 2026
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🧩 Analysis chain
🌐 Web query:
In C99/C11/C17, isuint_fast8_tguaranteed to be exactly 8 bits, or only at least 8 bits?💡 Result:
In C99, C11, and C17, the type uint_fast8_t is guaranteed to be an unsigned integer type with a width of at least 8 bits [1][2][3]. It is not guaranteed to be exactly 8 bits [4][5]. The C standard defines uint_fastN_t as the fastest unsigned integer type available on the implementation that has a width of at least N bits [1][3]. Because the implementation may choose a larger type (such as 16, 32, or 64 bits) if it is more efficient for the target architecture's word size or alignment requirements, uint_fast8_t can be wider than 8 bits [4][5]. In contrast, the type uint8_t is defined as an unsigned integer type with a width of exactly 8 bits, but it is an optional type and is not guaranteed to be provided by all implementations [2][6]. If an implementation does not support an 8-bit type, uint8_t will not be defined, whereas uint_fast8_t and uint_least8_t are required to be provided [1][4][3].
Citations:
🏁 Script executed:
head -60 DEVLOG.md | tail -20Repository: DavidCozens/solid-syslog
Length of output: 1010
Correct
uint_fast8_tdescription from "8-bit" to at least 8 bits.At lines 52–53, the note describes
uint_fast8_tas "8-bit". In C,uint_fast8_tis guaranteed to be at least 8 bits and may be wider (16, 32, or 64 bits) on many targets. The phrasing is misleading in technical documentation.Consider clarifying:
Proposed revision
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