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Extra Lab 8 - LAMBDA please repeat. #127

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164 changes: 145 additions & 19 deletions lab-python-lambda-map-reduce-filter.ipynb
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Original file line number Diff line number Diff line change
Expand Up @@ -94,12 +94,32 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 2,
"id": "0781335d-39cf-403d-b86a-ca908a09fe55",
"metadata": {},
"outputs": [],
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Debits found:\n",
"[(-1200, 'debit'), (-100, 'debit'), (-250, 'debit'), (-300, 'debit'), (-850, 'debit')]\n"
]
}
],
"source": [
"# your code goes here"
"transactions = [\n",
" (-1200, 'debit'), (2500, 'credit'), (-100, 'debit'), \n",
" (850, 'credit'), (-250, 'debit'), (1500, 'credit'), \n",
" (-300, 'debit'), (5000, 'credit'), (-850, 'debit'), (1000, 'credit')\n",
"]\n",
"\n",
"# Using filter() with a lambda function\n",
"# The lambda takes 'x' (a tuple) and checks if x[1] is 'debit'\n",
"debits = list(filter(lambda x: x[1] == 'debit', transactions))\n",
"\n",
"print(\"Debits found:\")\n",
"print(debits)"
]
},
{
Expand Down Expand Up @@ -127,9 +147,26 @@
"execution_count": null,
"id": "25073469-7258-4fc6-b0a0-ef8ea57688fe",
"metadata": {},
"outputs": [],
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Debits sorted in descending order (closest to 0 first):\n",
"[(-100, 'debit'), (-250, 'debit'), (-300, 'debit'), (-850, 'debit'), (-1200, 'debit')]\n"
]
}
],
"source": [
"# your code goes here"
"# 1. Define the lambda to extract the amount for sorting\n",
"# Note: In Python 3, sorted() uses 'key' to determine the sorting value.\n",
"sort_key = lambda x: x[0]\n",
"\n",
"# 2. Use sorted() with the key and reverse=True for descending order\n",
"sorted_debits = sorted(debits, key=sort_key, reverse=True)\n",
"\n",
"print(\"Debits sorted in descending order (closest to 0 first):\")\n",
"print(sorted_debits)"
]
},
{
Expand Down Expand Up @@ -169,12 +206,32 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 4,
"id": "2f253b7e-5300-4819-b38f-9fc090554f51",
"metadata": {},
"outputs": [],
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Balances after one year of interest:\n",
"[105.0, 52.5, -26.25, 1050.0, -10.5]\n"
]
}
],
"source": [
"# your code goes here"
"# Initial list of bank account balances\n",
"balances = [100, 50, -25, 1000, -10]\n",
"\n",
"# Interest rate\n",
"interest_rate = 0.05\n",
"\n",
"# 1. Use map() with a lambda function\n",
"# The lambda takes 'b' (balance) and multiplies it by 1.05\n",
"new_balances = list(map(lambda b: b * (1 + interest_rate), balances))\n",
"\n",
"print(\"Balances after one year of interest:\")\n",
"print(new_balances)"
]
},
{
Expand Down Expand Up @@ -209,12 +266,38 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 5,
"id": "0906a9b0-d567-4786-96f2-5755611b885e",
"metadata": {},
"outputs": [],
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Updated Accounts:\n",
"{'balance': 1020.0, 'interest_rate': 0.02}\n",
"{'balance': 2020.0, 'interest_rate': 0.01}\n",
"{'balance': 515.0, 'interest_rate': 0.03}\n"
]
}
],
"source": [
"# your code goes here\n"
"accounts = [\n",
" {'balance': 1000, 'interest_rate': 0.02},\n",
" {'balance': 2000, 'interest_rate': 0.01},\n",
" {'balance': 500, 'interest_rate': 0.03},\n",
"]\n",
"\n",
"# The lambda takes 'acc' (the dictionary)\n",
"# It returns a NEW dictionary with the updated balance\n",
"updated_accounts = list(map(lambda acc: {\n",
" 'balance': acc['balance'] * (1 + acc['interest_rate']),\n",
" 'interest_rate': acc['interest_rate']\n",
"}, accounts))\n",
"\n",
"print(\"Updated Accounts:\")\n",
"for account in updated_accounts:\n",
" print(account)"
]
},
{
Expand Down Expand Up @@ -243,14 +326,36 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 6,
"id": "6284dbd3-e117-411e-8087-352be6deaed4",
"metadata": {},
"outputs": [],
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Negative balances found: [-26.25, -10.5]\n",
"Total amount of debt: -36.75\n"
]
}
],
"source": [
"from functools import reduce\n",
"\n",
"# your code goes here"
"# Result from Challenge 2 Exercise 1 (balances after 0.05 interest)\n",
"# balances was [100, 50, -25, 1000, -10]\n",
"# after 1.05 interest: [105.0, 52.5, -26.25, 1050.0, -10.5]\n",
"new_balances = [105.0, 52.5, -26.25, 1050.0, -10.5]\n",
"\n",
"# 1. Filter the negative balances\n",
"negative_balances = list(filter(lambda x: x < 0, new_balances))\n",
"\n",
"# 2. Reduce to find the total sum of negatives\n",
"# reduce(function, iterable, initializer)\n",
"total_negative_amount = reduce(lambda a, b: a + b, negative_balances, 0)\n",
"\n",
"print(f\"Negative balances found: {negative_balances}\")\n",
"print(f\"Total amount of debt: {total_negative_amount}\")"
]
},
{
Expand All @@ -273,24 +378,45 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 7,
"id": "da2264b5-298e-4b45-99df-852b94e90d15",
"metadata": {},
"outputs": [],
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Remaining Balances:\n",
"[650, 1600, 275]\n"
]
}
],
"source": [
"accounts = [\n",
" {'balance': 1000, 'withdrawals': [100, 50, 200]},\n",
" {'balance': 2000, 'withdrawals': [300, 100]},\n",
" {'balance': 500, 'withdrawals': [50, 100, 75]},\n",
"]\n",
"\n",
"# your code goes here\n"
"# 1. Define the function for a single account\n",
"def calculate_balance(account):\n",
" \"\"\"\n",
" Subtracts the sum of all withdrawals from the initial balance.\n",
" \"\"\"\n",
" total_withdrawals = sum(account['withdrawals'])\n",
" return account['balance'] - total_withdrawals\n",
"\n",
"# 2. Use map to apply the function to the list of accounts\n",
"remaining_balances = list(map(calculate_balance, accounts))\n",
"\n",
"print(\"Remaining Balances:\")\n",
"print(remaining_balances)\n"
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Python 3 (ipykernel)",
"display_name": "base",
"language": "python",
"name": "python3"
},
Expand All @@ -304,7 +430,7 @@
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython3",
"version": "3.9.13"
"version": "3.13.9"
}
},
"nbformat": 4,
Expand Down