Solved

solutions.sql

@@ -0,0 +1,128 @@
+use sakila;
+
+--  1: Número de películas por categoría
+--  Listar cuántas pelis tiene cada género.
+--  Tablas: category -> film_category
+
+SELECT 
+    c.name AS category_name, 
+    COUNT(fc.film_id) AS film_count
+FROM film_category AS fc
+RIGHT JOIN category AS c 
+    ON c.category_id = fc.category_id
+GROUP BY 
+    c.name;
+
+
+--  2: Ubicación de las tiendas
+--  Sacar ID tienda, ciudad y país.
+--  Tablas: store -> address -> city -> country
+
+SELECT 
+    s.store_id, 
+    ci.city, 
+    co.country
+FROM store AS s
+INNER JOIN address AS a 
+    ON s.address_id = a.address_id
+INNER JOIN city AS ci 
+    ON a.city_id = ci.city_id
+INNER JOIN country AS co 
+    ON ci.country_id = co.country_id;
+
+
+--  3: Ingresos por tienda
+--  Total de dinero recaudado por tienda.
+--  store -> staff -> payment
+
+SELECT 
+    s.store_id, 
+    SUM(p.amount) AS total_revenue
+FROM store AS s
+INNER JOIN staff AS st 
+    ON s.store_id = st.store_id
+INNER JOIN payment AS p 
+    ON st.staff_id = p.staff_id
+GROUP BY 
+    s.store_id;
+
+
+--   4: Duración media por categoría
+--   Calcular la duración media de las películas de cada género.
+--   Tablas: category -> film_category -> film
+
+SELECT 
+    c.name AS category_name, 
+    AVG(f.length) AS average_duration
+FROM category AS c
+INNER JOIN film_category AS fc 
+    ON c.category_id = fc.category_id
+INNER JOIN film AS f 
+    ON fc.film_id = f.film_id
+GROUP BY 
+    c.name;
+
+
+-- 5: Categorías más largas
+-- Identificar qué géneros tienen la mayor duración media.
+-- Tablas: category -> film_category -> film
+
+SELECT 
+    c.name AS category_name, 
+    AVG(f.length) AS average_duration
+FROM category AS c
+INNER JOIN film_category AS fc 
+    ON c.category_id = fc.category_id
+INNER JOIN film AS f 
+    ON fc.film_id = f.film_id
+GROUP BY 
+    c.name
+ORDER BY 
+    average_duration DESC;    
+
+
+--  6 : Top 10 películas más alquiladas
+--  Mostrar los títulos que más veces se han alquilado.
+--  Tablas: film -> inventory -> rental
+SELECT 
+    f.title, 
+    COUNT(r.rental_id) AS rental_count
+FROM film AS f
+INNER JOIN inventory AS i 
+    ON f.film_id = i.film_id           
+INNER JOIN rental AS r 
+    ON i.inventory_id = r.inventory_id 
+GROUP BY 
+    f.title
+ORDER BY 
+    rental_count DESC                  
+LIMIT 10;
+
+--   7: Disponibilidad de pelicula en en tienda 1
+--   Comprobar si 'Academy Dinosaur' está en el inventario de la tienda 1.
+--   Tablas: film -> inventory
+SELECT 
+    f.title, 
+    i.store_id, 
+    i.inventory_id
+FROM film AS f
+INNER JOIN inventory AS i 
+    ON f.film_id = i.film_id
+WHERE 
+    f.title = 'ACADEMY DINOSAUR' 
+    AND i.store_id = 1;
+
+
+--   8: Estado del inventario (Available / NOT available)
+--   Listar todos los títulos y etiquetar si tenemos copias o no.
+--   Tablas: film -> inventory
+
+SELECT DISTINCT 
+    f.title,
+    CASE 
+        WHEN IFNULL(i.inventory_id, 0) = 0 THEN 'NOT available'
+        ELSE 'Available'
+    END AS availability_status
+FROM film AS f
+LEFT JOIN inventory AS i 
+    ON f.film_id = i.film_id;