Lab solved

lab-sql-joins.sql

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+USE SAKILA;
+
+#1
+SELECT  
+		 fc.category_id,
+         c.name AS category_name,
+         count(fc.film_id) AS film_count
+FROM film_category fc
+INNER JOIN category c
+	ON c.category_id = fc.category_id
+GROUP BY fc.category_id, c.name
+ORDER BY fc.category_id;
+
+#2
+SELECT s.store_id,
+    c.city,
+    co.country
+FROM store s
+INNER JOIN address a
+	ON a.address_id = s.address_id
+INNER JOIN city c
+	ON c.city_id = a.city_id
+INNER JOIN country co
+	ON c.country_id = co.country_id;
+
+#3
+SELECT 
+	  st.store_id,
+	  SUM(p.amount) as revenue
+FROM payment p
+INNER JOIN staff s
+	ON p.staff_id = s.staff_id
+INNER JOIN store st 
+	ON s.store_id = st.store_id
+GROUP BY st.store_id
+ORDER BY st.store_id;
+
+#4
+SELECT c.name,
+	  COUNT(f.film_id) AS film_count,
+	   ROUND(AVG(f.length),2) AS avg_length
+FROM film f
+INNER JOIN film_category fc
+	ON f.film_id = fc.film_id
+INNER JOIN category c
+	ON fc.category_id = c.category_id
+GROUP BY c.name;
+
+
+#5
+SELECT c.name,
+	   ROUND(AVG(f.length),2) AS avg_length
+FROM film f
+INNER JOIN film_category fc
+	ON f.film_id = fc.film_id
+INNER JOIN category c
+	ON fc.category_id = c.category_id
+GROUP BY c.name
+ORDER BY avg_length DESC
+LIMIT 5;
+
+#6
+SELECT f.film_id,
+	f.title, 
+COUNT(r.inventory_id) AS rental_count
+FROM rental r
+INNER JOIN inventory i
+	ON r.inventory_id = i.inventory_id
+INNER JOIN film f
+	ON i.film_id = f.film_id
+GROUP BY f.title, f.film_id
+ORDER BY rental_count DESC
+LIMIT 10;
+
+#7
+SELECT *
+FROM inventory
+WHERE film_id = 1 
+	 AND store_id = 1;
+
+#8     
+SELECT 
+    f.title,
+    CASE 
+        WHEN COUNT(i.inventory_id) = 0 THEN 'NOT available'
+        ELSE 'Available'
+    END AS availability_status
+FROM film f
+LEFT JOIN inventory i
+    ON f.film_id = i.film_id
+GROUP BY f.film_id, f.title
+ORDER BY f.title;