"Solved Lab: SQL Joins"

joins-lab.sql

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+USE sakila;
+
+-- 1. List the number of films per category
+SELECT 
+    c.name AS category,
+    COUNT(fc.film_id) AS number_of_films
+FROM category c
+JOIN film_category fc 
+    ON c.category_id = fc.category_id
+GROUP BY c.name
+ORDER BY number_of_films DESC;
+
+
+-- 2. Retrieve the store ID, city, and country for each store
+SELECT 
+    s.store_id,
+    ci.city,
+    co.country
+FROM store s
+JOIN address a 
+    ON s.address_id = a.address_id
+JOIN city ci 
+    ON a.city_id = ci.city_id
+JOIN country co 
+    ON ci.country_id = co.country_id;
+
+
+-- 3. Calculate the total revenue generated by each store in dollars
+SELECT 
+    s.store_id,
+    SUM(p.amount) AS total_revenue
+FROM store s
+JOIN staff st 
+    ON s.store_id = st.store_id
+JOIN payment p 
+    ON st.staff_id = p.staff_id
+GROUP BY s.store_id;
+
+
+-- 4. Determine the average running time of films for each category
+SELECT 
+    c.name AS category,
+    AVG(f.length) AS avg_running_time
+FROM film f
+JOIN film_category fc 
+    ON f.film_id = fc.film_id
+JOIN category c 
+    ON fc.category_id = c.category_id
+GROUP BY c.name
+ORDER BY avg_running_time DESC;
+
+
+-- BONUS
+
+-- 5. Identify the film categories with the longest average running time
+SELECT 
+    c.name AS category,
+    AVG(f.length) AS avg_running_time
+FROM film f
+JOIN film_category fc 
+    ON f.film_id = fc.film_id
+JOIN category c 
+    ON fc.category_id = c.category_id
+GROUP BY c.name
+ORDER BY avg_running_time DESC
+LIMIT 1;
+
+
+-- 6. Display the top 10 most frequently rented movies
+SELECT 
+    f.title,
+    COUNT(r.rental_id) AS rental_count
+FROM rental r
+JOIN inventory i 
+    ON r.inventory_id = i.inventory_id
+JOIN film f 
+    ON i.film_id = f.film_id
+GROUP BY f.title
+ORDER BY rental_count DESC
+LIMIT 10;
+
+
+-- 7. Determine if "Academy Dinosaur" can be rented from Store 1
+SELECT 
+    f.title,
+    i.store_id,
+    COUNT(i.inventory_id) AS copies_available
+FROM film f
+JOIN inventory i 
+    ON f.film_id = i.film_id
+WHERE f.title = 'Academy Dinosaur'
+AND i.store_id = 1
+GROUP BY f.title, i.store_id;
+
+
+-- 8. List all distinct film titles with availability status
+SELECT 
+    f.title,
+    CASE
+        WHEN COUNT(i.inventory_id) > 0 THEN 'Available'
+        ELSE 'NOT available'
+    END AS availability
+FROM film f
+LEFT JOIN inventory i 
+    ON f.film_id = i.film_id
+GROUP BY f.title
+ORDER BY f.title;