Lab Solved

lab-sql-joins-solved.sql

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+-- Write SQL queries to perform the following tasks using the Sakila database:
+-- 1. List the number of films per category.
+USE sakila;
+
+SELECT  c.name AS category, COUNT(fc.film_id) AS number_of_films FROM sakila.category AS c
+LEFT JOIN sakila.film_category AS fc
+ON c.category_id = fc.category_id
+GROUP BY category;
+
+-- 2. Retrieve the store ID, city, and country for each store.
+SELECT s.store_id, c.city, co.country FROM sakila.store AS s
+LEFT JOIN sakila.address AS a
+ON s.address_id = a.address_id
+LEFT JOIN sakila.city AS c
+ON a.city_id = c.city_id
+LEFT JOIN sakila.country AS co
+ON c.country_id = co.country_id;
+
+-- 3. Calculate the total revenue generated by each store in dollars.
+SELECT s.store_id , SUM(p.amount) AS total_revenue FROM sakila.payment AS p
+JOIN sakila.staff AS s
+ON p.staff_id = s.staff_id
+JOIN sakila.store AS st
+ON s.store_id = st.store_id
+GROUP BY s.store_id;
+
+-- 4. Determine the average running time of films for each category.
+SELECT c.name AS category, ROUND(AVG(f.length),2) AS average_running_time FROM sakila.film AS f
+JOIN sakila.film_category AS fc
+ON f.film_id = fc.film_id
+JOIN sakila.category AS c
+ON c.category_id = fc.category_id
+GROUP BY c.name;
+
+
+-- Bonus:
+-- 5. Identify the film categories with the longest average running time.
+SELECT c.name AS category, ROUND(AVG(f.length),2) AS average_running_time FROM sakila.film AS f
+JOIN sakila.film_category AS fc
+ON f.film_id = fc.film_id
+JOIN sakila.category AS c
+ON c.category_id = fc.category_id
+GROUP BY c.name
+ORDER BY average_running_time DESC;
+
+-- 6. Display the top 10 most frequently rented movies in descending order.
+SELECT f.title AS movie, COUNT(r.rental_id) AS times_rented FROM sakila.film AS f
+JOIN sakila.inventory AS i
+ON f.film_id = i.film_id
+JOIN sakila.rental AS r
+ON i.inventory_id = r.inventory_id
+GROUP BY f.title, f.film_id
+ORDER BY times_rented DESC
+LIMIT 10;
+
+-- 7. Determine if "Academy Dinosaur" can be rented from Store 1.
+SELECT f.title, i.store_id, i.inventory_id FROM sakila.film AS f
+JOIN sakila.inventory AS i
+ON f.film_id = i.film_id
+WHERE f.title = 'Academy Dinosaur'
+AND i.store_id = 1;
+
+-- 8. Provide a list of all distinct film titles, along with their availability status in the inventory. 
+-- Include a column indicating whether each title is 'Available' or 'NOT available.' 
+-- Note that there are 42 titles that are not in the inventory, and this information can be obtained using a CASE statement combined with IFNULL."
+SELECT f.title,
+    CASE 
+        WHEN COUNT(i.inventory_id) = 0 THEN 'NOT available'
+        ELSE 'Available'
+    END AS availability_status
+FROM sakila.film AS f
+LEFT JOIN sakila.inventory AS i
+ON f.film_id = i.film_id
+GROUP BY f.film_id, f.title;