Solved lab

joins.sql

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+USE sakila;
+
+-- 1. List the number of films per category
+SELECT
+    c.name AS category,
+    COUNT(fc.film_id) AS number_of_films
+FROM category c
+JOIN film_category fc
+    ON c.category_id = fc.category_id
+GROUP BY c.name
+ORDER BY number_of_films DESC;
+
+-- 2. Retrieve the store ID, city, and country for each store
+SELECT
+    s.store_id,
+    ci.city,
+    co.country
+FROM store s
+JOIN address a
+    ON s.address_id = a.address_id
+JOIN city ci
+    ON a.city_id = ci.city_id
+JOIN country co
+    ON ci.country_id = co.country_id
+ORDER BY s.store_id;
+
+-- 3. Calculate the total revenue generated by each store in dollars
+SELECT
+    s.store_id,
+    ROUND(SUM(p.amount), 2) AS total_revenue
+FROM store s
+JOIN staff st
+    ON s.store_id = st.store_id
+JOIN payment p
+    ON st.staff_id = p.staff_id
+GROUP BY s.store_id
+ORDER BY s.store_id;
+
+-- 4. Determine the average running time of films for each category
+SELECT
+    c.name AS category,
+    ROUND(AVG(f.length), 2) AS avg_running_time
+FROM category c
+JOIN film_category fc
+    ON c.category_id = fc.category_id
+JOIN film f
+    ON fc.film_id = f.film_id
+GROUP BY c.name
+ORDER BY avg_running_time DESC;
+
+-- Bonus 1: Identify the film categories with the longest average running time
+SELECT
+    c.name AS category,
+    ROUND(AVG(f.length), 2) AS avg_running_time
+FROM category c
+JOIN film_category fc
+    ON c.category_id = fc.category_id
+JOIN film f
+    ON fc.film_id = f.film_id
+GROUP BY c.name
+ORDER BY avg_running_time DESC
+LIMIT 1;
+
+-- Bonus 2: Display the top 10 most frequently rented movies in descending order
+SELECT
+    f.title,
+    COUNT(r.rental_id) AS times_rented
+FROM film f
+JOIN inventory i
+    ON f.film_id = i.film_id
+JOIN rental r
+    ON i.inventory_id = r.inventory_id
+GROUP BY f.film_id, f.title
+ORDER BY times_rented DESC, f.title ASC
+LIMIT 10;
+
+-- Bonus 3: Determine if 'Academy Dinosaur' can be rented from Store 1
+SELECT
+    f.title,
+    i.store_id,
+    CASE
+        WHEN COUNT(i.inventory_id) > 0 THEN 'Yes'
+        ELSE 'No'
+    END AS can_be_rented
+FROM film f
+LEFT JOIN inventory i
+    ON f.film_id = i.film_id
+    AND i.store_id = 1
+WHERE f.title = 'Academy Dinosaur'
+GROUP BY f.title, i.store_id;
+
+-- Bonus 4: List all distinct film titles with availability status in inventory
+SELECT
+    f.title,
+    CASE
+        WHEN COUNT(i.inventory_id) > 0 THEN 'Available'
+        ELSE 'NOT available'
+    END AS availability_status
+FROM film f
+LEFT JOIN inventory i
+    ON f.film_id = i.film_id
+GROUP BY f.film_id, f.title
+ORDER BY f.title;